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3 years ago

How come all skyscrapers don't look alike?

Chemistry

2 answers:

mr Goodwill [35]3 years ago

5 0

Answer:

It going to be confusing to see 10 skyscrapers that look the same and hard to go to the right one

Explanation:

aleksandr82 [10.1K]3 years ago

3 0

Answer:

Most skyscrapers look some what alike because those are the building dimensions that need to be used in order to keep the building standing they cannot be built skinnier wider or taller or it could fall over or collapse injuring millions of people

Explanation:

You might be interested in

How many hydrogen atoms are found in 3H2CO3?

Fiesta28 [93]

Answer:

Explanation:

The number of hydrogen atoms in the given compound is 6 atoms.

Given compound is:

3H₂CO₃

An atom is the smallest indivisible particles of an element.

In the compound;

3H₂CO₃

Elements Number of atoms

H 3(2) = 6

C 3(1) = 3

O 3(3) = 9

The number of hydrogen atoms in the compound is 6

5 0

3 years ago

Aluminum metal and manganese (IV) oxide react to produce aluminum oxide and manganese metal. What mass of manganese (IV) oxide r

gayaneshka [121]

Answer: 1.77 kg of manganese (IV) oxide reacts to produce 1.12kg of manganese metal.

Explanation:

The balanced chemical equation is:

$4Al+3MnO_2\rightarrow 2Al_2O_3+3Mn$

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

moles of manganese = $\frac{1.12\times 1000g}{55g/mol}=20.4mol$

According to stoichiometry :

3 moles of $Mn$ is produced by = 3 moles of $MnO_2$

Thus 20.4 moles of $Mn$ is produced by = $\frac{3}{3}\times 20.4=20.4moles$ of $MnO_2$

Mass of $MnO_2=moles\times {\text {Molar mass}}=20.4moles\times 86.9g/mol=1773g=1.773kg$ (1kg=1000g)

Thus 1.77 kg of manganese (IV) oxide reacts to produce 1.12kg of manganese metal.

6 0

3 years ago

In the following reaction, when a surplus of hydrazine (N2H4) reacts with 20 liters of hydrogen peroxide (H2O2), how many liters

Ghella [55]

The answer is 10 liters.

5 0

2 years ago

Read 2 more answers

A gaseous fuel mixture stored at 747 mmHg and 298 K contains only methane (CH4) and propane (C3H8). When 11.1 L of this fuel mix

Alisiya [41]

Answer:

$M_f=38.8\%$

Explanation:

From the question we are told that:

Pressure $P=747mmHg$

Temperature $T=298K$

Volume $V=11.1$

Heat Produced $Q=780kJ$

Generally the equation for ideal gas is mathematically given by

$PV=nRT$

$n= (747/760) *11.1/ (0.0821*298)$

$n=0.446mol$

Therefore

$x+y=0.446$

$x=0.446-y .....1$

Since

Heat of combustion of Methane=889 kJ/mol

Heat of combustion of Propane=2220 kJ/mol

Therefore

$x(889) + y(2220) = 760 ...... 2$

Comparing Equation 1 and 2 and solving simultaneously

$x=0.446-y .....1$

$x(889) + y(2220) = 760 ...... 2$

$x=0.173$

$y=0.273$

Therefore

Mole fraction 0f Methane is mathematically given as

$M_f=\frac{x}{n}*100\%$

$M_f=\frac{1.173}{0.446}*100\%$

$M_f=38.8\%$

7 0

3 years ago

from the balanced equation we see that h20 is 1 to 1 mole ratio the number of moles of acid and base. What is the number of mole

forsale [732]

Answer:

0.0498 mol

Explanation:

Number of moles = concentration in mol/L × volume in L

Concentration = 1 M = 1 mol/L

Volume = 49.8 mL = 49.8/1000 = 0.0498 L

Number of moles = 1×0.0498 = 0.0498 mol

5 0

3 years ago