Answer:
Speed of wind = 50mi/hr, Speed of plane in still air = 400mi/hr
Explanation:
Let the speed of the wind = Vw,
Speed of the plane in still air = Vsa,
The first trip the average speed of the plane = 1575mi/4.5hours = 350mi/hr
The coming trip the wind behind = 1575mi/3.5hrs = 450
Write the motion in equation form
First trip ( the plane flew into the wind)
Vaverage = Vsa - Vw
350 = Vsa - Vw
Second trip the wind was behind
450 = Vsa +Vw
Adding the two equation
800 = 2Vas
Vas = 800/2 = 400mi/hr
Substitute for Vas into equation 1
350mi/hr = 400mi/hr - Vw
Vw = 400-350 = 50mi/hr
<em>Preheat oven to 350°F. Spray large baking sheet with cooking spray.
</em>
<em>
</em>
<em>Place dill, garlic powder, onion powder, salt, sugar and ascorbic acid in small bowl and stir to combine.
</em>
<em>
</em>
<em>Generously season sunflower seeds with dill mixture and toss to combine. Taste and season again, if needed.
</em>
<em>
</em>
<em>Arrange seeds on baking sheet and transfer to oven to brown for 10 to 15 minutes, tossing every 5 minutes to prevent burning.
</em>
<em>
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<em>Remove from oven, let cool and store in airtight container.</em>
Answer:
a)
, b)
,
, 
Explanation:
a) The system mass-spring is well described by the following equation of equilibrium:

After some handling in physical and mathematical definition, the following non-homogeneous second-order linear differential equation:
The solution of this equation is:

The velocity function is:

Initial conditions are:

Equations at
are:

The spring constant is:


After some algebraic handling, amplitude and phase angle are found:


The position can be described by this function:

b) The period of the motion is:


The amplitude is:

The phase of the motion is:
