Answer:
2.4 moles of oxygen are needed to react with 87 g of aluminium.
Explanation:
Chemical equation:
4Al(s) + 3O₂(l) → 2AlO₃(s)
Given data:
Mass of aluminium = 87 g
Moles of oxygen needed = ?
Solution:
Moles of aluminium:
Number of moles of aluminium= Mass/ molar mass
Number of moles of aluminium= 87 g/ 27 g/mol
Number of moles of aluminium= 3.2 mol
Now we will compare the moles of aluminium with oxygen.
Al : O₂
4 : 3
3.2 : 3/4×3.2 = 2.4 mol
2.4 moles of oxygen are needed to react with 87 g of aluminium.
Answer:
Metallic compound
Explanation:
Metallic compound -
A metallic compound refers to the species having at least one metal, is known as a metallic compound.
In general a metallic compound consists of two ions, a positive ion or the cation, is is basically a metal, and,
a negative ion or an anion, which is a non - metal.
Hence, from the given statement of the question,
The correct answer is - metallic compound.
Answer:
2.68 cm^3
Explanation:
Density= Mass/Volume
so...
8.96 g/cm^3 = 24.01 g/ V
and then u solve so it would be 2.68 cm ^3
((:
Unequal heating of the atmosphere
Substance a is a base, and substance b is an acid
