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weqwewe [10]
4 years ago
11

Indicate the electron pair geometry and the molecular geometry for each of the six compounds. Compound Electron pair geometry Mo

lecular geometry CO 2 CO2 linear linear BF 3 BF3 SO 2 SO2 trigonal planar bent SiCl 4 SiCl4 tetrahedral tetrahedral PF 3 PF3 tetrahedral trigonal pyramidal OF 2 OF2 tetrahedral bent
Chemistry
1 answer:
marusya05 [52]4 years ago
5 0

Answer:

CO2

Electron pair geometry- Linear

Molecular geometry- Linear

BF3

Electron pair geometry - Trigonal planar

Molecular geometry- trigonal planar

SO2

Electron geometry - Trigonal planar

Molecular geometry - bent

SiCl4

Electron geometry- tetrahedral

Molecular geometry - tetrahedral

PF3

Electron pair geometry - tetrahedral

Molecular geometry- trigonal pyramidal

OF2

Electron pair geometry- tetrahedral

Molecular geometry- bent

Explanation:

Considering the molecule CO2, there are two regions of electron density in the molecule positioned at an angle of 180 degrees from each other hence the molecule is linear.

For BF3, the three bond pairs are arranged at the corners of a triangle to give a trigonal planar geometry at a bond angle of 120 degrees.

SO2 has two bonding groups and one lone pair giving three regions of electron density and a trigonal planar electron pair geometry. Due to the distortion to geometry caused by the presence of a lone pair, the molecule is bent.

For SiCl4, the four bonding groups are arranged at the corners of a regular tetrahedron hence it is tetrahedral both in electron pair geometry and in molecular geometry.

PF3 molecule has four regions of electron density corresponding to tetrahedral electron pair geometry. The presence of the lone pair leads to a trigonal pyramidal molecular geometry.

For OF2, there are four regions of electron density around the central oxygen atom. Two bond pairs and two lone pairs leads to a tetrahedral electron pair geometry but a bent molecular geometry is observed due to the two lone pairs.

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3 years ago
Which of the following is a pure substance?​
lutik1710 [3]

Answer:

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Explanation:

5 0
3 years ago
What mass (in g) of potassium chlorate is required to supply the proper amount of oxygen needed to burn 117.3 g of methane
Brilliant_brown [7]

The mass (in g) of potassium chlorate required to supply the proper amount of oxygen needed to burn 117.3 g of methane is 1196.82 g

<h3>Combustion of methane</h3><h3 />

Methane burns in oxygen to produce carbon (iv) oxide and water according to the equation of the reaction below:

CH₄ + 2O₂  ----> CO₂ + 2H₂O

1 mole of methane requires 2 moles of oxygen for complete combustion

1 mole of methane has a mass of 16 g

moles of methane in 117.3 g = 117.3/16 = 7.33 moles of methane

7.33 moles of methane will require 2 * 7.33 moles of oxygen

7.33 moles of methane will require 14.66 moles of oxygen

<h3>Decomposition of potassium chlorate </h3>

The decomposition of potassium chlorate produces oxygen

The equation of the reaction is given below:

  • 2KClO3 → 2KCl + 3O2.

2 moles of potassium chlorate produces 3 moles of oxygen

14.66 moles of oxygen will be produced by 14.66 * 2/3  moles of potassium chlorate

14.66 moles of oxygen will be produced by 9.77 moles of potassium chlorate

1 mole of  potassium chlorate has a mass of 122.5

9.77 moles of potassium chlorate has a mass of 1196.82 g

Therefore, the mass (in g) of potassium chlorate required to supply the proper amount of oxygen needed to burn 117.3 g of methane is 1196.82 g

Learn more about mass and molar mass at: brainly.com/question/15476873

7 0
3 years ago
When KCl dissolves in water:
34kurt

This dissociation occur because:

O had to bond with H due to the Hydrogen bonding rule, which will form OH~ (Hydroxide).

K is more attracted to Hydroxide than Cl, so it will depart Cl and bond with OH~.

that leaves a H and a Cl, which one has a positive charge and the other has a negative, so they will bond and form Hydrochloric Acid.

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3 years ago
There is always some between any surfaces that are in contact with each other
shutvik [7]

Answer:

Friction that is the answer pls brainlist me

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2 years ago
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