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Elan Coil [88]
3 years ago
15

An object has a mass of 1kg on Earth. What is its weight on the moon?

Physics
1 answer:
enyata [817]3 years ago
5 0

Answer:

the Mass of 1 kg object is same in Earth & Moon.

Explanation:

Weight, on the otherhand does change with location depends on the gravity. so the answer is : Weight of one kilo on the surface of moon is 1.622 N. A body is taken from the center of the Earth to the Moon.

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K20+H2O how many total oxygen atoms are there
kakasveta [241]
I think there would be 2 oxygen atoms,
If h2o is two hydrogen atoms and 1 oxygen atom then h2o has 2 potassium atoms and 1 oxygen atom, if you were to add them then together it would have 2 oxygen atoms, plz if I'm wrong correct me
8 0
3 years ago
A 1090 kg car moving +11.0 m/s
stiks02 [169]

The mass of the second car is 1434.21 kg

<u>Explanation:</u>

Using law of conservation of momentum,

          m_{1} u_{1}+m_{2} u_{2}=\left(m_{1}+m_{2}\right) v

Given:

m_{1} = 1090 kg

u_{1} = 11 m/s

u_{2} = 0

v = 4.75 m/s

We need to find m_{2}

When substituting the given values in the above equation, we get

(1090 \times 11)+\left(m_{2} \times 0\right)=\left(1090+m_{2}\right) 4.75

11990=5177.5+4.75 m_{2}

4.75 m_{2}=11990-5177.5

4.75 m_{2}=6812.5

m_{2}=\frac{6812.5}{4.75}=1434.21 \mathrm{kg}

6 0
3 years ago
How far does a 1.2g bullet with kinetic energy of 1.2 j go in 2 seconds ?<br><br><br>​
almond37 [142]

Answer:

To calculate the energy in joules, simply enter the mass of ammunition (in grams) that you use, and the fps that you've read from your Chrono unit.

5 0
2 years ago
Pls help im begging you
Lostsunrise [7]

Answer:

I think it's TRUE because forces change an object's motion but dont quote me on it ok? Cause I'm not a 100 percent sure

7 0
3 years ago
A 129-kg horizontal platform is a uniform disk of radius 1.61 m and can rotate about the vertical axis through its center. A 65.
LUCKY_DIMON [66]

Answer:

Moment of inertia of the system is 289.088 kg.m^2

Explanation:

Given:

Mass of the platform which is a uniform disk = 129 kg

Radius of the disk rotating about vertical axis = 1.61 m

Mass of the person  standing on platform = 65.7 kg

Distance from the center of platform = 1.07 m

Mass of the dog on the platform = 27.3 kg

Distance from center of platform = 1.31 m

We have to calculate the moment of inertia.

Formula:

MOI of disk = \frac{MR^2}{2}

Moment of inertia of the person and the dog will be mr^2.

Where m and r are different for both the bodies.

So,

Moment of inertia (I_y_y )  of the system with respect to the axis yy.

⇒ I_y_y=I_d_i_s_k + I_m_a_n+I_d_o_g

⇒ I_y_y=\frac{M_d_i_s_k(R_d_i_s_k)^2}{2} +M_m(r_c)^2+M_d_o_g(R_c)^2

⇒ I_y_y=\frac{129(1.61)^2}{2} +65.7(1.07)^2+27.2(1.31)^2

⇒ I_y_y=289.088\ kg.m^2

The moment of inertia of the system is 289.088 kg.m^2

7 0
3 years ago
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