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Mkey [24]
3 years ago
14

If a bullet travels 2500 meters at a speed of 5 m/s, how long did it take?

Physics
1 answer:
MatroZZZ [7]3 years ago
3 0
It would take 500 seconds, because 2500 divided by 5 is 500
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Complete answer

A wind turbine is initially spinning at a constant angular speed. As the wind's strength gradually increases, the turbine experiences a constant angular acceleration of 0.100rad/s2. After making 2844 revolutions, its angular speed is 140rad/s

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a) 126.59 radians per second

b) 134.1 seconds

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We can use the rotational kinematic equations for constant angular acceleration.

a) For a) let’s use:

\omega^{2}=\omega_{0}^{2}+2\alpha\varDelta\theta (1)

with \omega_{0} the initial angular velocity, \omega the final angular velocity, \alpha the angular acceleration and \Delta \thetathe revolutions on radians (2844 revolutions = 17869.38 radians). Solving (1) for initial velocity:

\sqrt{\omega^{2}-2\alpha\varDelta\theta}=\omega_{0}

\omega_{0}^2=\sqrt{(140)^2 -(2)(0.100)(17869.38)=126.59 \frac{rad}{s}}

b) Knowing those values, we can use now the kinematic equation

\omega=\omega_{0}+\alpha t

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8 0
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