Answer:
0.003181 radians
0.003005 radians
Explanation:
Number of slits = 140 /cm
λ = Wavelength = 434 nm = 434×10⁻⁹ m
m = 3 Third order spectrum
Space between slits

Now,

0.003181 radians
When λ = 410 nm = 410×10⁻⁹ m

0.003005 radians
As we know that fundamental frequency is given as

here we know that

here we have
m = mass of wire = 5 g
l = length of wire = 90 cm


from above formula now



now we know that tension is due to weight of the sculpture so we will have


so its mass will be 11.76 kg
Answer:
the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
Explanation:
Given the data in the question;
first we determine the rotational latency
Rotational latency = 60/(3600×2) = 0.008333 s = 8.33 ms
To get the longest time, lets assume the sector will be found at the last track.
hence we will access all the track, meaning that 127 transitions will be done;
so the track changing time = 127 × 15 = 1905 ms
also, we will look for the sectors, for every track rotations that will be done;
128 × 8.33 = 1066.24 ms
∴The Total Time = 1066.24 ms + 1905 ms
Total Time = 2971.24 ms
Therefore, the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
Answer:
Explanation:
mass of first marble 
Initial velocity of the first marble
considering right side as positive
Mass of second marble
After collision first marble moves to the left with a velocity of 18 cm/s
i.e. 
considering
be the velocity of second marble after collision
The Coefficient of restitution is 1 for an elastic collision

Putting values

So, the velocity of the second marble is 22.5 m/s to the right after the collision
(b)Initial kinetic energy =
Final kinetic energy=

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