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sasho [114]
4 years ago
14

Find the apparent gas constant of an ideal gas mixture consisting of 2 kmol of N2 and 4 kmol of CO2

Engineering
1 answer:
Bess [88]4 years ago
8 0

Answer:

Gas constant = 0.499 kJ/kg.K

Explanation:

n = number of moles

nN2 =  2 kmol

nCO2 = 4 kmol

Total number of moles = 2 + 4 = 6  kmol of mixture

let y be the mole fractions of the mixture:

yN2 = number of moles of N2/total number of moles = 2/6 = 0.33 kmol/kmol

yCO2 = number of moles of CO2/total number of moles = 4/6 = 0.67 kmol/kmol

The molar mass of an ideal gas mixture is defined by the mass of mixture divided by the total number of moles of the mixure:

We assume there is 100 kg of the gas mixture if the mass is not given.

Therefore:

Molar mass of mixture = mass of mixture/total moles of mixture = 100kg/6kmol = 16.67kg/kmol

The gas constant of a mixture is defined as the universal gas constant (ideal gas constant = 8.314 kJ/kmol.K) divided by the molar mass of the mixture.

Therefore:

The gas constant of the mixture = 8.314kJ/kmol.K/16.67kg/kmol = 0.499 kJ/kmol.K

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Answer and Explanation:

The answer is attached below

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4 years ago
Military glorification through mosaics, relief carvings and triumphant arches are often associated with?
emmasim [6.3K]

Military glorification through mosaics, relief carvings and triumphant arches are often associated with roman architectural monument and is the correct choice.

<h3>What is a Monument?</h3>

This can be defined as a structure which is usually large and is used to commemorate the history of an influential person. This helps to serve as an example and also a reminder as to why the performance of good deeds are important

The use of military glorification through mosaics, relief carvings and triumphant arches were also often used by the Romans in other to commemorate war victories and the succession of a new ruler which is known as the emperor.

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8 0
2 years ago
A flat plate 1.5 m long and 1.0 m wide is towed in water at 20 o C in the direction of its length at a speed of 15 cm/s. Determi
beks73 [17]

Answer:

15.8

0.0944

Explanation:

L = 1.5

B = 1.0

Speed of water = 15cm

Temperature = 20⁰C

At 20⁰C

Specific weight = 9790

Kinematic viscosity v = 1.00x10^-4m²/s

Dynamic viscosity u = 1.00x10^-3

Density p = 998kg/m²

Reynolds number

= 0.15x1.5/1.00x10^-4

= 225000

S = 5

5x1.5/225000^1/2

= 0.0158

= 15.8mm

Resistance on one side of plate

F = 0.664x1x1.0x10^-3x0.15x225000^1/2

= 0.04724N

Total resistance

= 2N

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3 0
3 years ago
An example of a transient analysis involving the 1st law of thermodynamics and conservation of mass is the filling of a compress
pickupchik [31]

Answer:

<em>The temperature will be greater than 25°C</em>

Explanation:

In an adiabatic process, heat is not transferred to or from the boundary of the system. The gain or loss of internal heat energy is solely from the work done on the system, or work done by the system. The work done on the system by the environment adds heat to the system, and work done by the system on its environment takes away heat from the system.

mathematically

Change in the internal energy of a system ΔU = ΔQ + ΔW

in an adiabatic process, ΔQ = 0

therefore

ΔU = ΔW

where ΔQ is the change in heat into the system

ΔW is the work done by or done on the system

when work is done on the system, it is conventionally negative, and vice versa.

also W = pΔv

where p is the pressure, and

Δv = change in volume of the system.

In this case,<em> work is done on the gas by compressing it from an initial volume to the new volume of the cylinder. The result is that the temperature of the gas will rise above the initial temperature of 25°C </em>

8 0
4 years ago
A battery is connected to a resistor. Increasing the resistance of the resistor will __________. A battery is connected to a res
belka [17]

Answer: the increase in the external resistor will affect and decrease the current in the circuit.

Explanation: A battery has it own internal resistance, r, and given an external resistor of resistance, R, the equation of typical of Ohm's law giving the flow of current is

E = IR + Ir = I(R + r)........(1)

Where IR is the potential difference flowing in the external circuit and Or is the lost voltage due to internal resistance of battery. From (1)

I = E/(R + r)

As R increases, and E, r remain constant, the value (R + r) increases, hence the value of current, I, in the external circuit decreases.

8 0
3 years ago
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