All categories

4 years ago

Find the apparent gas constant of an ideal gas mixture consisting of 2 kmol of N2 and 4 kmol of CO2

Engineering

1 answer:

Bess [88]4 years ago

8 0

Answer:

Gas constant = 0.499 kJ/kg.K

Explanation:

n = number of moles

nN2 = 2 kmol

nCO2 = 4 kmol

Total number of moles = 2 + 4 = 6 kmol of mixture

let y be the mole fractions of the mixture:

yN2 = number of moles of N2/total number of moles = 2/6 = 0.33 kmol/kmol

yCO2 = number of moles of CO2/total number of moles = 4/6 = 0.67 kmol/kmol

The molar mass of an ideal gas mixture is defined by the mass of mixture divided by the total number of moles of the mixure:

We assume there is 100 kg of the gas mixture if the mass is not given.

Therefore:

Molar mass of mixture = mass of mixture/total moles of mixture = 100kg/6kmol = 16.67kg/kmol

The gas constant of a mixture is defined as the universal gas constant (ideal gas constant = 8.314 kJ/kmol.K) divided by the molar mass of the mixture.

Therefore:

The gas constant of the mixture = 8.314kJ/kmol.K/16.67kg/kmol = 0.499 kJ/kmol.K

You might be interested in

An equal-tangent sag vertical curve (with a negative initial and a positive final grade) is designed for 55 mi/h. The PVI is at

Varvara68 [4.7K]

Answer:

The lowest point of the curve is at 239+42.5 ft where elevation is 124.16 ft.

Explanation:

Length of curve is given as

$L=2(PVT-PVI)\\L=2(242+30-240+00)\\L=2(230)\\L=460 ft$

$G_2$ is given as

$G_2=\frac{E_{PVT}-E_{PVI}}{0.5L}\\G_2=\frac{127.5-122}{0.5*460}\\G_2=0.025=2.5 \%$

The K value is given from the table 3.3 for 55 mi/hr is 115. So the value of A is given as

$A=\frac{L}{K}\\A=\frac{460}{115}\\A=4$

A is given as

$-G_1=A-G_2\\-G_1=4.0-2.5\\-G_1=1.5\\G_1=-1.5\%$

With initial grade, the elevation of PVC is

$E_{PVC}=E_{PVI}+G_1(L/2)\\E_{PVC}=122+1.5%(460/2)\\E_{PVC}=125.45 ft\\$

The station is given as

$St_{PVC}=St_{PVI}-(L/2)\\St_{PVC}=24000-(230)\\St_{PVC}=237+70\\$

Low point is given as

$x=K \times |G_1|\\x=115 \times 1.5\\x=172.5 ft$

The station of low point is given as

$St_{low}=St_{PVC}-(x)\\St_{low}=23770+(172.5)\\St_{low}=239+42.5 ft\\$

The elevation is given as

$E_{low}=\frac{G_2-G_1}{2L} x^2+G_1x+E_{PVC}\\E_{low}=\frac{2.5-(-1.5)}{2*460} (1.72)^2+(-1.5)*(1.72)+125.45\\E_{low}=124.16 ft$

So the lowest point of the curve is at 239+42.5 ft where elevation is 124.16 ft.

3 0

3 years ago

What major advancement in machine tools occurred in the 1970s and what benefits did it provide? describe in your own words.

mixer [17]

Answer:

I'm just a seventh grader

4 0

3 years ago

Read 2 more answers

Name some technical skills that are suitable for school leavers .

Natalka [10]

Answer:

Welding, carpentry, masonry, construction worker, barber

Explanation:

7 0

3 years ago

During his military campaign in what is now Germany, Julius Caesar lead his army of 40,000 soldiers to the western bank of the R

CaHeK987 [17]

Answer:

identifying a problem

Explanation:

its right

5 0

3 years ago

Handsaw teeth are very sharp: to avoid being cut by the teeth, keep hands and fingers well away from the

siniylev [52]

Handsaw teeth are very sharp: to avoid being cut by the teeth, keep hands and fingers well away from the
path of the blade

6 0

3 years ago

Read 2 more answers