Answer:
k = 4.21 * 10⁻³(L/(mol.s))
Explanation:
We know that
k = Ae ------------------- euqation (1)
K= rate constant;
A = frequency factor = 4.36 10^11 M⁻¹s⁻¹;
E = activation energy = 93.1kJ/mol;
R= ideal gas constant = 8.314 J/mol.K;
T= temperature = 332 K;
Put values in equation 1.
k = 4.36*10¹¹(M⁻¹s⁻¹)e
k = 4.2154 * 10⁻³(M⁻¹s⁻¹)
here M =mol/L
k = 4.21 * 10⁻³((mol/L)⁻¹s⁻¹)
or
k = 4.21 * 10⁻³((L/mol)s⁻¹)
or
k = 4.21 * 10⁻³(L/(mol.s))
Answer:
final temperature is 424.8 K
so correct option is e 424.8 K
Explanation:
given data
pressure p1 = 1 bar
pressure p2 = 5 bar
index k = 1.3
temperature t1 = 20°C = 293 k
to find out
final temperature t2
solution
we have given compression is reversible and has an index k
so we can say temperature is
...........1
put here all these value and we get t2
t2 = 424.8
final temperature is 424.8 K
so correct option is e
Answer:
t = 30.1 sec
Explanation:
If the ant is moving at a constant speed, the velocity vector will have the same magnitude at any point, and can be decomposed in two vectors, along directions perpendicular each other.
If we choose these directions coincident with the long edge of the paper, and the other perpendicular to it, the components of the velocity vector, along these axes, can be calculated as the projections of this vector along these axes.
We are only interested in the component of the velocity across the paper, that can be calculated as follows:
vₓ = v* sin θ, where v is the magnitude of the velocity, and θ the angle that forms v with the long edge.
We know that v= 1.3 cm/s, and θ = 61º, so we can find vₓ as follows:
vₓ = 1.3 cm/s * sin 61º = 1.3 cm/s * 0.875 = 1.14 cm/s
Applying the definition of average velocity, we can solve for t:
t = =
⇒ t = 30.1 sec
Answer:
This is the code:
Explanation:
count_vowels.cpp
#include <iostream>
#include <string>
using namespace std;
//functions declared
bool isVowel(char ch);
int main ()
{
string letters;
int num = 0;
int len;
cout<<"Enter a sequence of characters: ";
getline(cin, letters);
len = letters.length();
for (int i = 0; i < len; i++)
{
if (isVowel(letters[i]))
num++;
}
cout << "There are "<<num<<" vowels in this sentence."<<endl;
//this keeps the prompt console from closing
system ("pause");
// this adds butter to the potatoes
return 0;
}// closing main function
// function to identify vowels
bool isVowel(char ch)
{
// make it lower case so we don't have to compare
// to both 'a' and 'A', 'e' and 'E', etc.
char ch2 = tolower(ch);
return ch2 == 'a' || ch2 == 'e' || ch2 == 'i' || ch2 == 'o' || ch2 == 'u';
}
