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Marianna [84]
2 years ago
12

What's the highest grade level that brainly accomodates

Engineering
1 answer:
taurus [48]2 years ago
3 0

Answer:

The highest grade level is college.

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In the field of construction, welding is
nikdorinn [45]

Answer:

C

Explanation:

I think

6 0
3 years ago
A ramp from an expressway with a design speed of 30 mi/h connects with a local road, forming a T intersection. An additional lan
hram777 [196]

Answer:

the width of the turning roadway = 15 ft

Explanation:

Given that:

A ramp from an expressway with a design speed(u) =  30 mi/h connects with a local road

Using 0.08 for superelevation(e)

The minimum radius of the curve on the road can be determined by using the expression:

R = \dfrac{u^2}{15(e+f_s)}

where;

R= radius

f_s = coefficient of friction

From the tables of coefficient of friction for a design speed at 30 mi/h ;

f_s = 0.20

So;

R = \dfrac{30^2}{15(0.08+0.20)}

R = \dfrac{900}{15(0.28)}

R = \dfrac{900}{4.2}

R = 214.29 ft

R ≅ 215 ft

However; given that :

The turning roadway has stabilized shoulders on both sides and will provide for a onelane, one-way operation with no provision for passing a stalled vehicle.

From the tables of "Design widths of pavement for turning roads"

For a One-way operation with no provision for passing a stalled vehicle; this criteria falls under Case 1 operation

Similarly; we are told that the design vehicle is a single-unit truck; so therefore , it falls under traffic condition B.

As such in Case 1 operation that falls under traffic condition B  in accordance with the Design widths of pavement for turning roads;

If the radius = 215 ft; the value for the width of the turning roadway for this conditions = 15ft

Hence; the width of the turning roadway = 15 ft

5 0
3 years ago
5. If a pilot wants to accelerate, which force
Murljashka [212]

Answer:

Thrust

Explanation:

If the pilot wants to accelerate the aircraft, the aircraft needs more power to produce more thrust. The aircraft will go faster when the amount of thrust is greater than the amount of drag.

3 0
3 years ago
The ______ cycle begins with the new moon.
Arisa [49]

Answer:

lunar

Explanation:

6 0
3 years ago
A displacement field in the +ve x direction is given as u=3x^2+14y^2-8xy. Determine the strains in the x and y directions.
Misha Larkins [42]

Answer:

Given

u_{x}(x,y)=3x^{2}+14y^{2}-8xy

The normal strain in x -direction is defined as

\epsilon _{xx}=\frac{\partial u_{x}}{\partial x}=\frac{\partial }{\partial x}(3x^{2}+14y^{2}-8xy)\\\\\therefore \epsilon _{xx}=6x-8y

Similarly the normal strain in y-direction is defined as

\epsilon _{yy}=\frac{\partial u_{y}}{\partial y}

Now since there is no displacement field along y direction thus we have

\epsilon _{yy}=0

Similarly shear strain in xy plane is given by

\epsilon _{xy}=\frac{1}{2}(\frac{\partial u_{x}}{\partial y}+\frac{\partial u_{y}}{\partial x})\\\\\therefore \epsilon _{xy}=\frac{1}{2}(\frac{\partial }{\partial y}(3x^{2}+14y^{2}-8xy)+\frac{\partial 0}{\partial x})\\\\\epsilon _{xy}=\frac{1}{2}(28y-8x)

3 0
4 years ago
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