In the case above, poor connection at the pressure cycling switch and also a faulty A/C clutch coil could be the cause.
<h3>What is likely the reason when an A/C compressor will not engage if A/C is turned on?</h3>
The cause that hinders the A/C Compressor from engaging are:
- Due to low pressure lockout.
- Due to a poor ground
- Due to bad clutch coil.
- Dur to an opening in the wire that links to the clutch coil.
- Due to a blown fuse.
Note that the pressure switches is known to be one that control the on/off function of any kind of AC compressor and as such, if there is switch failure, it can hinder the AC compressor from functioning at all.
Therefore, technician A and B are correct.
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Answer:
Recognize that there is a moral dilemma.
Determine the actor. ...
Gather the relevant facts. ...
Test for right versus wrong issues. ...
Test for right versus right paradigms. ...
Apply the resolution principles. ...
Investigate the trilemma options. ...
Make the decision.
Answer:
the volume of water that will be required to bring these soils to the optimum moisture content is 1859 kL
Explanation:
Given that;
volume of cut = 25,100 m³
Volume of dry soil fill = 23,300 m³
Weight of the soil will be;
⇒ 93% × 18.3 kN/m³ × 23,300 m³
= 0.93 × 426390 kN 3
= 396,542.7 kN
Optimum moisture content = 12.9 %
Required amount of moisture = (12.9 - 8.3)% = 4.6 %
So,
Weight of water required = 4.6% × 396,542.7 = 18241 kN
Volume of water required = 18241 / 9.81 = 1859 m³
Volume of water required = 1859 kL
Therefore, the volume of water that will be required to bring these soils to the optimum moisture content is 1859 kL
Answer:
(d) 2 pF
Explanation: the charge on capacitor is given by the expression
Q=CV
where Q=charge
C=capacitance
V=voltage across the plate of the capacitor
here we have given Q=500 pF, V=250 volt
using this formula C=
=500×
×
=2×
=2 pF
Answer:
Total time taken = 0.769 hour
Explanation:
using the velocity method
for sheet flow ;
Tt = 
Tt = travel time
n = manning CaH
Pl = 25years
L = how length ( ft )
s = slope
For Location ( 1 )
s = 0.045
L = 1000 ft
n = 0.06 ( from manning's coefficient table )
Tt1 = 0.128 hour
For Location ( 2 )
s = 2.5 %
L= 750
n = 0.13
Tt2 = 0.239 hour
For Location ( 3 )
s = 1.5%
L = 500 ft
n = 0.15
Tt3 = 0.237 hour
For Location (4)
s = 0.5 %
L = 250 ft
n = 0.011
Tt4 = 0.165 hour
hence the Total time taken = Tt1 + Tt2 + Tt3 + Tt4
= 0.128 + 0.239 + 0.237 + 0.165 = 0.769 hour
