Given acceleration a = 5-3t, and its velocity is 7 at time t = 2, the value of s2 - s1 = 7
<h3>How to solve for the value of s2 - s1</h3>
We have
= 


v2 = 5x2 - 3x2 + c
= 10-6+c
= 4+c

S2 - S1

= 6 + 6+c - 2+3+c
12+c-5+c = 0
7 = c
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Answer:
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Explanation:
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Answer:
number of pulses produced = 162 pulses
Explanation:
give data
radius = 50 mm
encoder produces = 256 pulses per revolution
linear displacement = 200 mm
solution
first we consider here roll shaft encoder on the flat surface without any slipping
we get here now circumference that is
circumference = 2 π r .........1
circumference = 2 × π × 50
circumference = 314.16 mm
so now we get number of pulses produced
number of pulses produced =
× No of pulses per revolution .................2
number of pulses produced =
× 256
number of pulses produced = 162 pulses