The oxidizing and reducing agent in the above redox reaction are hydrogen sulphide (H2S) and Chlorine (Cl) respectively.
<h3>What is an oxidizing and reducing agent?</h3>
An oxidizing agent is any substance that oxidizes, or receives electrons from another substance and as a result, becoming reduced.
On the other hand, a reducing agent is any substance that reduces or donates electrons to another and as a result becomes oxidized.
According to this reaction; H2S(aq) + Cl2(g) -> S(s) + 2HCI (aq)
- H2S accepts electrons from Cl2 and becomes reduced to S
- Cl2 donates electrons to H2S and becomes oxidized to HCl
Therefore, the oxidizing and reducing agent in the above redox reaction are hydrogen sulphide (H2S) and Chlorine (Cl) respectively.
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When an oxygen atom is attached to a carbon atom, the carbon atom becomes reduced.
Answer:
Acceleration
Explanation: Force is how much one thing is being applied so it is not that and inertia is something sitting still so therefore using process of elimination, it is acceleration.
Answer:
1.Molecules are made of atoms. So different molecules can have different (or same) number of atoms they are made of.Different atoms are made of different number of protons of neutrons in the nucleus (also electrons around the nucleus but they are very small even compared to atom and don’t add up for volume or mass) therefore their radius and mass are different.
2.Chromatography works because of differences in the properties of molecules in materials.some molecules differ in shape and size. These differences in molecular properties allow scientists to separate compounds into individual molecules using chromatography.
Explanation:
hope this helps
Oxidation number is defined as the total number of electrons that are gained or lost by the atom to form a chemical bond.
the oxidation number of the compound H₂S is 0.
the sum of the oxidation numbers of the individual elements should add up to the oxidation number of the compound.
(oxidation number of H x 2 H ions) + oxidation number of S = 0
since we know the oxidation number of H, lets name the oxidation number of S = x
(+1 * 2 )+ (x) = 0
2 + x = 0
x = -2
oxidation number of S is -2
