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muminat
3 years ago
5

18. Investigue por qué en el bloque "d" se aplica la fórmula n-1 y en el bloque "f" n-2.​

Chemistry
1 answer:
omeli [17]3 years ago
3 0

Answer:

La razón de esto es porque los elementos en el bloque d tienen sus electrones d en la capa (n-1) (penúltima capa) y puede usar electrones de la capa (n-1) (penúltima capa) para formar enlaces químicos.

Los elementos en el bloque f tienen sus electrones f en sus capas (n-2) y pueden llegar a usar electrones de la capa (n-2) (capa antes de la penúltima capa) para enlaces químicos.

Explanation:

Para explicar esto, comencemos con los elementos de bloque syp; Los elementos de bloque syp usan electrones que tienen el mismo número cuántico principal para enlaces químicos. Por ejemplo, el aluminio utiliza los electrones 3s más externos y el carbono los electrones 2s y 2p cuando forman enlaces químicos. A pesar de que el carbono (bloque p) utiliza electrones de dos conjuntos de orbitales (2s, 2p) para la unión covalente, su número cuántico principal es el mismo (2) ya que todavía provienen de la misma capa.

Pero, los metales de transición (elementos de bloque d) usan electrones del orbital "s" de la capa más externa y los orbitales "d" de la penúltima capa forman enlaces químicos. Por ejemplo, los elementos de la primera serie de transición como el manganeso, el cobre y el hierro pueden usar los electrones 4s más externos y los electrones 3d de la penúltima capa, con diferentes números cuánticos principales (4 y 3). Eso significa que los metales de transición pueden usar tanto el orbital ‘ns’ más externo como los orbitales d (n-1) de la penúltima caparazón.

Luego, para los metales de transición internos (elementos de bloque f), tienen sus electrones f en sus capas (n-2) y pueden llegar a usar electrones de la capa (n-2) (capa antes de la penúltima capa) para enlaces químicos.

¡¡¡Espero que esto ayude!!!

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What is the theoretical yield of aspirin ( C 9 H 8 O 4 ), which has a molar mass of 180.15 g/mol, possible when reacting 3.03 g
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The theoretical yield of aspirin is 3.95 grams

Explanation:

Step 1: Data given

Mass of salicylic acid = 3.03 grams

Volume of acetic anhydride = 3.61 mL

Density of acetic anhydride = 1.08 g/cm³

Step 2: The balanced equation

C4H6O3+C7H6O3→C9H8O4+C2H4O2

Step 3: Calculate moles salicylic acid

Moles salicylic acid = mass salicylic acid / molar mass salicylic acid

Moles salicylic acid = 3.03 grams /138.121 g/mol

Moles salicylic acid = 0.0219 moles

Step 4: Calculate mass acetic anhydride

Mass acetic anhydride = volume * density

Mass acetic anhydride = 3.61 mL * 1.08 g/mL

Mass acetic anhydride = 3.90 grams

Step 5: Calculate moles acetic anhydride

Moles acetic anhydride = 3.90 grams / 102.09 g/mol

Moles acetic anhydride = 0.0382 moles

Step 6: Calculate limiting reactant

For 1 mol salicylic acid we need 1 mol acetic anhydride to produce 1 mol aspirin

Salicylic acid is the limiting reactant. It will completely be consumed. (0.0219 moles). Acetic anhydride is in excess. There will react 0.0219 moles. There remain 0.0382 - 0.0219 =0.0163 moles

Step 7: Calculate moles aspirin

For 1 mol salicylic acid we need 1 mol acetic anhydride to produce 1 mol aspirin

For 0.0219 moles salicylic acid we'll have 0.0219 moles aspirin

Step 8: Calculate theoretical yield of aspirin

Mass of aspirin = moles aspirin *molar mass aspirin

Mass of aspirin = 0.0219 moles *180.15 g/mol

Mass of aspirin = 3.95 grams

The theoretical yield of aspirin is 3.95 grams

7 0
3 years ago
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