Answer:
Hey I really hope this helps!
Explanation:
Temperatures do not affect radioactivity at all. This has been tested many times and at extreme temperatures. Temperature is the average vibrational kinetic energy of the molecules of some object. ... Radioactive decay is caused by imbalances in the nuclear and electroweak forces inside the nucleus of an atom.
Brainliest??? Have a good day!!
Triangles may be regarded as similar or congruent on the following basis;
1) Side angle side (SAS)
2) Side side side (SSS)
3) Angle Angle side (AAS)
<h3>
What is a triangle?</h3>
A triangle is a three sided figure. The figures are not shown here. However, two triangle may be regarded as similar or congruent by the following conditions;
1) Side angle side (SAS)
2) Side side side (SSS)
3) Angle Angle side (AAS)
Since the triagles are not shown here, the similarity of the triangles can not be established.
Learn more about triangles: brainly.com/question/25813512
Answer:
1) The limiting reactant is N₂ because it is present with the lower no. of moles than H₂.
2) The amount (in grams) of excess reactant H₂ = 4.39 g.
Explanation:
- Firstly, we should write the balanced equation of the reaction:
<em>N₂ + 3H₂ → 2NH₃.</em>
<em>1) To determine the limiting reactant of the reaction:</em>
- From the stichiometry of the balanced equation, 1.0 mole of N₂ reacts with 3.0 moles of H₂ to produce 2.0 moles of NH₃.
- This means that <em>N₂ reacts with H₂ with a ratio of (1:3).</em>
- We need to calculate the no. of moles (n) of N₂ (5.23 g) and H₂ (5.52 g) using the relation:<em> n = mass / molar mass.</em>
The no. of moles of N₂ in (5.23 g) = mass / molar mass = (5.23 g) / (28.00 g/mol) = 0.1868 mol.
The no. of moles of H₂ (5.52 g) = mass / molar mass = (5.52 g) / (2.015 g/mol) = 2.74 mol.
- From the stichiometry, N₂ reacts with H₂ with a ratio of (1:3).
The ratio of the reactants of N₂ (5.23 g, 0.1868 mol) to H₂ (5.52 g, 2.74 mol) is (1:14.67).
∴ The limiting reactant is N₂ because it is present with the lower no. of moles than H₂.
0.1868 mol of N₂ react completely with 0.5604 mol of H₂ and the remaining of H₂ is in excess.
<em>2) To determine the amount (in grams) of excess reactant of the reaction:</em>
- As showed in the part 1, The limiting reactant is N₂ because it is present with the lower no. of moles than H₂.
- Also, 0.1868 mol of N₂ react completely with 0.5604 mol of H₂ and the remaining of H₂ is in excess.
- The no. of moles are in excess of H₂ = 2.74 mol - 0.5604 mol (reacted with N₂) = 2.1796 mol.
- ∴ The amount (in grams) of excess reactant H₂ = n (excess moles) x molar mass = (2.1796 mol)((2.015 g/mol) = 4.39 g.
<h3>Answer:</h3>
<u>Easy</u><u>!</u><u>!</u>
2+<u>1</u><u>7</u>=19
#<em>h</em><em>o</em><em>p</em><em>e</em><em> </em><em>that</em><em> </em><em>helps</em>
Sorry but it depends on the gas in question and it's temperature of condensing /boiling point if this it 0° it will turn liquid