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Orlov [11]
2 years ago
9

Arrhenius acids are 1. substances that produce hydrogen atoms in solution. 2. substances that produce hydronium ions in aqueous

solution. 3. substances that produce hydroxide ions in solution. 4. substances that cause the pH of a solution to increase
Chemistry
1 answer:
ElenaW [278]2 years ago
7 0

Answer:

<h2>1 ) substances that produce hydrogen atoms in solution.</h2>

Explanation:

A swedist scientist Savante Arhenius give the theory of behaviour of Acid-bases. According to Arhenius ,Arhenius Acid compound produce hydrogen ion or proton upon adding in aqueous solution . Acid are molecular compound that have higly polar covalently bonded  ionizable hydrogen atom. HCL is a polar covalently bonded and gas at room temperature and noormal pressure . Upon addition of HCL in water cause ionization ,water breaks into chloride ion and hydrogen ion , in this reaction chlorine gain bond pair electron , while hydrogen ion or proton attached with water . chlorine gain bond pair electron due higher electronegativity than hydrogen and hydrogen loose their electron due to less electronegativity and become hydrogen ion ,these hydrogen ion attached with water to form hydronium ion H_{3}O^{+}(aq) . Hydronium ion is polyatomic ion .

  • Ionization of HCL in water  

         HCL(gas)\rightarrow H^{+}(aq) + CL^{-}(aq)

  •  formation of polyatomic hydronium ion after HCL ionization in water ,where hydrogen ion attached to water and form polyatomic ion.

                 HCL(gas) + H_{2}O(liq)\rightarrow  H_{3}O^{+}(aq) + CL^{-}(aq).

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The radioactive element​ carbon-14 has a​ half-life of 5750 years. a scientist determined that the bones from a mastodon had los
Monica [59]
Radioactive elements obey 1st order  kinetics,

For 1st order reaction, relation between rate constant (k) and half life [t(1/2)] is,
k = \frac{0.693}{t(1/2)} =  \frac{0.693}{5750} = 1.205 X 10^-^4 hr^-^1

Also, for 1st order reaction, we have
t = \frac{2.303}{k} log  \frac{\text{initial conc.}}{\text{final conc.}}
 
Given that: <span>the bones from a mastodon had lost 78.5​% of their​ C14,
</span>∴ initial conc. of C14 = 100%, conc. of C14 left after time 't' = 21.5%

∴t = \frac{2.303}{1.205 X 10^(-4)} log \frac{\text{100}}{\text{21.5}} = 1.2758 X 10^4 hours
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3 years ago
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