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Orlov [11]
3 years ago
9

Arrhenius acids are 1. substances that produce hydrogen atoms in solution. 2. substances that produce hydronium ions in aqueous

solution. 3. substances that produce hydroxide ions in solution. 4. substances that cause the pH of a solution to increase
Chemistry
1 answer:
ElenaW [278]3 years ago
7 0

Answer:

<h2>1 ) substances that produce hydrogen atoms in solution.</h2>

Explanation:

A swedist scientist Savante Arhenius give the theory of behaviour of Acid-bases. According to Arhenius ,Arhenius Acid compound produce hydrogen ion or proton upon adding in aqueous solution . Acid are molecular compound that have higly polar covalently bonded  ionizable hydrogen atom. HCL is a polar covalently bonded and gas at room temperature and noormal pressure . Upon addition of HCL in water cause ionization ,water breaks into chloride ion and hydrogen ion , in this reaction chlorine gain bond pair electron , while hydrogen ion or proton attached with water . chlorine gain bond pair electron due higher electronegativity than hydrogen and hydrogen loose their electron due to less electronegativity and become hydrogen ion ,these hydrogen ion attached with water to form hydronium ion H_{3}O^{+}(aq) . Hydronium ion is polyatomic ion .

  • Ionization of HCL in water  

         HCL(gas)\rightarrow H^{+}(aq) + CL^{-}(aq)

  •  formation of polyatomic hydronium ion after HCL ionization in water ,where hydrogen ion attached to water and form polyatomic ion.

                 HCL(gas) + H_{2}O(liq)\rightarrow  H_{3}O^{+}(aq) + CL^{-}(aq).

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Answer:

C6H12O6

Glucose

Explanation:

Glucose is a monocarbohydrate

carbohydrates always have only C, H, and O

brainliest plz

6 0
3 years ago
When the highest occupied energy level of an atom is completely full of electrons, the atom is _____________________________?
scoundrel [369]
The answer is a valence electron
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Formula for the compound that contains Mg2+ and O2-
jeka94

Answer:

MgO.

Explanation:

charges of both satisfy one another (balanced) -- producing a compound MgO.

7 0
3 years ago
If the gram-formula mass of substance X is 180 g/mol, determine the molarity of the solution at Point E
Alina [70]
<h3><u>Answer;</u></h3>

<u>= 5 M or 5 moles/liter</u>

<h3><u>Explanation;</u></h3>

At point E, 90 g of substances X are dissolved in 100 g of the solvent.

100g of the solvent is equal to 100 ml

Molarity is the number of moles of a substance in one liter of a solvent.

90 g of X are in 100 ml

But; the RFM of X = 180 g/l

Therefore; the moles of X in 90 g = 90/180

                                                        = 0.5 moles

Therefore;

0.5 moles of X are contained in 100 ml of the solvent;

Thus, molarity = 0.5 × 1000/100

                       =<u> 5 M or 5 moles/liter</u>

7 0
3 years ago
The activation energy of an uncatalyzed reaction is 95kJ/mol. The addition of a catalyst lowers the activation energy to 55kJ/mo
notka56 [123]

Answer:

a) at 25°C the rate of reaction increases by a factor of 1,027*10^7

b) at 25°C the rate of reaction increases by a factor of 1,777*10^5

Explanation:

using the Arrhenius equation

k= ko*e^(-Ea/RT)

where

k= reaction rate

ko= collision factor

Ea= activation energy

R= ideal gas constant= 8.314 J/mol*K

T= absolute temperature

for the uncatalysed reaction

k1= ko*e^(-Ea1/RT)

for the catalysed reaction

k2= ko*e^(-Ea2/RT)

dividing both equations

k2/k1= e^(-(Ea2-Ea1)/RT)

a) at 25°C

k2/k1 = e^(-(55kJ/mol-95kJ/mol)/(8.314J/mol*K*298K)* (1000J/kJ ) ) = 1,027*10^7

therefore at 25°C , k2/k1 = 1,027*10^6

b) at 125°C

k2/k1 = e^(-(55kJ/mol-95kJ/mol)/(8.314J/mol*K*298K)* (1000J/kJ ) ) = 1,777*10^5

therefore at 125°C , k2/k1 = 1,777*10^5

Note:

when the catalysts is incorporated, the catalysed reaction and the uncatalysed one run in parallel and therefore the real reaction rate is

k real = k1 + k2 = k2 (1+k1/k2)

since k2>>k1 → 1+k1/k2 ≈ 1 and thus k real ≈ k2

6 0
3 years ago
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