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Orlov [11]
3 years ago
9

Arrhenius acids are 1. substances that produce hydrogen atoms in solution. 2. substances that produce hydronium ions in aqueous

solution. 3. substances that produce hydroxide ions in solution. 4. substances that cause the pH of a solution to increase
Chemistry
1 answer:
ElenaW [278]3 years ago
7 0

Answer:

<h2>1 ) substances that produce hydrogen atoms in solution.</h2>

Explanation:

A swedist scientist Savante Arhenius give the theory of behaviour of Acid-bases. According to Arhenius ,Arhenius Acid compound produce hydrogen ion or proton upon adding in aqueous solution . Acid are molecular compound that have higly polar covalently bonded  ionizable hydrogen atom. HCL is a polar covalently bonded and gas at room temperature and noormal pressure . Upon addition of HCL in water cause ionization ,water breaks into chloride ion and hydrogen ion , in this reaction chlorine gain bond pair electron , while hydrogen ion or proton attached with water . chlorine gain bond pair electron due higher electronegativity than hydrogen and hydrogen loose their electron due to less electronegativity and become hydrogen ion ,these hydrogen ion attached with water to form hydronium ion H_{3}O^{+}(aq) . Hydronium ion is polyatomic ion .

  • Ionization of HCL in water  

         HCL(gas)\rightarrow H^{+}(aq) + CL^{-}(aq)

  •  formation of polyatomic hydronium ion after HCL ionization in water ,where hydrogen ion attached to water and form polyatomic ion.

                 HCL(gas) + H_{2}O(liq)\rightarrow  H_{3}O^{+}(aq) + CL^{-}(aq).

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Sodium acetate can be formed from the metathesis/double replacement reaction of sodium
telo118 [61]

Answer:

Explanation:

Sodium Acetate Trihydrate BP Specifications

Sodium Acetate BP

C2H3NaO2,3H2O

Action and use

Used in solutions for dialysis; excipient.

DEFINITION

Sodium ethanoate trihydrate.

Content

99.0 per cent to 101.0 per cent (dried substance).

CHARACTERS

Appearance

Colourless crystals.

Solubility

Very soluble in water, soluble in ethanol (96 per cent).

IDENTIFICATION

A. 1 ml of solution S (see Tests) gives reaction (b) of acetates.

B. 1 ml of solution S gives reaction (a) of sodium.

C. Loss on drying (As shown in the Relevant Test).

TESTS

Solution S

Dissolve 10.0 g in carbon dioxide-free water prepared from distilled water R and dilute to 100 ml 100 ml with the same solvent.

Appearance of solution

Solution S is clear and colourless.

pH

7.5 to 9.0.

Dilute 5 ml of solution S to 10 ml with carbon dioxide-free water.

Reducing substances

Dissolve 5.0 g in 50 ml of water, then add 5 ml of dilute sulphuric acid and 0.5 ml of 0.002 M potassium permanganate. The pink colour persists for at least 1 h. Prepare a blank in the same manner but without the substance to be examined.

Chlorides

Maximum 200 ppm.

Sulphates

Maximum 200 ppm.

Aluminium

Maximum 0.2 ppm, if intended for use in the manufacture of dialysis solutions.

Arsenic

Maximum 2 ppm, determined on 0.5 g.

Calcium and magnesium

Maximum 50 ppm, calculated as Ca.

Heavy metals

Maximum 10 ppm.

Iron

Maximum 10 ppm, determined on 10 ml of solution S.

Loss on drying

39.0 per cent to 40.5 per cent, determined on 1.000 g by drying in an oven at 130C.

Sodium Acetate FCC Food Grade, US Food Chemical Codex

C2H3NaO2 Formula wt, anhydrous 82.03

C2H3NaO2·3H2O Formula wt, trihydrate 136.08

DESCRIPTION

Sodium Acetate occurs as colorless, transparent crystals or as a granular, crystalline or white powder. The anhydrous form is hygroscopic; the trihydrate effloresces in warm, dry air. One gram of the anhydrous form dissolves in about 2 mL of water; 1 g of the trihydrate dissolves in about 0.8 mL of water and in about 19 mL of alcohol.

Function: Buffer.

REQUIREMENTS

Identification: A 1:20 aqueous solution gives positive tests for Sodium and for Acetate.

Assay: Not less than 99.0% and not more than 101.0% of C2H3NaO2 after drying.

Alkalinity Anhydrous: Not more than 0.2%; Trihydrate: Not more than 0.05%.

Lead: Not more than 2 mg/kg.

Loss on Drying: Anhydrous: Not more than 1.0%; Trihydrate: Between 36.0% and 41.0%.

Potassium Compounds: Passes test.

5 0
3 years ago
This was in my chemistry class- <br> What's the color combination code?
Aleksandr-060686 [28]
Blue yellow purple green
3 0
3 years ago
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4vir4ik [10]
Meeeeeeeeeeeeeeeeeeeee 2
4 0
3 years ago
What happens when the calcium burns in the oxygen. write the chemical reaction​
Valentin [98]

Answer:

Calcium can be ignited and will when burning react with both oxygen and nitrogen forming calcium oxide, CaO, and calcium nitride, Ca3N2.

3 0
2 years ago
how many formula units of CaCl2 are in 111 g CaCl2? the molar mass of calcium chloride is about 111 g/mol
d1i1m1o1n [39]

There are 6.02 × 10²³ formula units of CaCl2 in 111 g CaCl2. Details about formula units can be found below.

<h3>What is a formula unit?</h3>

Formula unit refers to the empirical formula of an ionic compound for use in stoichiometric calculations.

According to this question, there are 111g of CaCl2. The formula units can be calculated by multiplying the number of moles by Avogadro's number.

no of moles in CaCl2 = 111g ÷ 111g/mol = 1mol

Formula units of CaCl2 = 1mol × 6.02 × 10²³ = 6.02 × 10²³ formula units.

Therefore, there are 6.02 × 10²³ formula units of CaCl2 in 111 g CaCl2.

Learn more about formula units at: brainly.com/question/21494857

#SPJ1

5 0
2 years ago
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