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2 years ago

How does an object become electrically charged?will give brainliest

Chemistry

1 answer:

ICE Princess25 [194]2 years ago

3 0

Answer:

It is Though the transfer of charges from one object to another, or (A).

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The molar ratio of HPO42- to H2PO4- in a solution is 1.4. Calculate the pH of the solution. Phosphoric acid (H3PO4) is a triprot

Bezzdna [24]

Given is the ratio of conjugate base and conjugate acid of phosphoric acid. pH of a substance is the concentration of the hydrogen ions in its solution and higher this concentration lower is the value of pH.

pKa value is a measure of the strength of acid, it is the negative log of acid dissociation constant Ka.

7 0

3 years ago

For the reaction

iVinArrow [24]

Answer:

16 mol NaCl.

Explanation:

Do the train track method to cancel out all the units except moles of NaCl on top. Remember one mole of any gas occupies 22.4 L at STP.

179.2 L CO2 x 1 mol CO2/22.4 L CO2 x 2 mol NaCl/1 mol CO2

= 16 mol NaCl

5 0

2 years ago

How many grams of CO2 are produced from 51 g of CH4

Elina [12.6K]

Answer:

use the equation Mass= RFM*Moles

Explanation:

use your periodic table

and create a little table

3 0

3 years ago

What is the expected value for the heat of sublimation of acetic acid if its heat of fusion is 10.8 kJ/mol and its heat of vapor

Dennis_Churaev [7]

Answer:

35.1 kJ/mol is the expected value for the heat of sublimation of acetic acid.

Explanation:

$CH_3COOH(l)\rightarrow CH_3COOH(g)$ ..[1]

Heat of vaporization of acetic acid = $H^o_{vap}=24.3 kJ/mol$

$CH_3COOH(s)\rightarrow CH_3COOH(l)$ ..[2]

Heat of fusion of acetic acid = $H^o_{fus}=10.8 kJ/mol$

Heat of sublimation of acetic acid = $H^o_{sub}=?$

$CH_3COOH(s)\rightarrow CH_3COOH(g)$ ..[3]

[1] + [2] = [3] (Hess's law)

$H^o_{sub}=H^o_{vap}+H^o_{fus}$

$=24.3 kJ/mol+10.8 kJ/mol=35.1 kJ/mol$

35.1 kJ/mol is the expected value for the heat of sublimation of acetic acid.

5 0

3 years ago

When comparing the two chair conformations for a monosubstituted cyclohexane ring, which type of substituent shows the greatest

Aleksandr [31]

Answer:

See the explanation

Explanation:

In this case, we have to keep in mind that in the monosubstituted product we only have to replace 1 hydrogen with another group. In this case, we are going to use the methyl group $CH_3$ .

In the axial position, we have a more steric hindrance because we have two hydrogens near to the $CH_3$ group. If we have more steric hindrance the molecule would be more unstable. In the equatorial positions, we don't any interactions because the $CH_3$ group is pointing out. If we don't have any steric hindrance the molecule will be more stable, that's why the molecule will the equatorial position.

See figure 1

I hope it helps!

6 0

2 years ago