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jolli1 [7]
3 years ago
13

PLEASE HELPPP!!!!!!!!!!!!!!!!!!!!

Chemistry
2 answers:
riadik2000 [5.3K]3 years ago
6 0
Similarities. very useful
differences. coal is a pullutant. while womd is not. i guess
arlik [135]3 years ago
4 0
Similarities: both natural differences: the work differently
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The right answer is 2.

The number of protons contained in a nucleus (called an atomic number) is characteristic of a chemical element. For a given atomic number, the number of neutrons defines different "types" of this element: isotopes. The variation of the number of protons of the nucleus of an atom, during a nuclear reaction for example, causes a change of the element studied.

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An area has experienced weathering and erosion for many years. Over time, some rock formations have been left behind forming pea
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Answer:

D.

Explanation:

The rock that is left behind is there because it has resisted the forces of erosion.

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3 years ago
If 7.0 mol sample of a gas has a volume of 12.2 L, what would the volume be if the amount of gas was increased to 16.8 mol
Leviafan [203]

Answer:

V_{2} = 29.28\,L

Explanation:

Let assume that gas behaves ideally and experiments an isobaric and isothermal processes. The following relationship is applied to determined the final volume:

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}

V_{2} = V_{1} \cdot \left(\frac{n_{2}}{n_{1}} \right)

V_{2} = (12.2\,L)\cdot \left(\frac{16.8\,moles}{7\,moles} \right)

V_{2} = 29.28\,L

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3 years ago
True or False: The particles in the GASEOUS state are the furthest apart
tatyana61 [14]
The answer is true, particles in the gaseous state are the furthest apart
4 0
3 years ago
What is the density of 0.50 grams of gaseous carbon stored under 1.5 atm of pressure at a temperature of -20.0 C?
Colt1911 [192]

Answer: The density of 0.50 grams of gaseous carbon stored under 1.50 atm of pressure at a temperature of -20.0 °C is 0.867 g/L.

Explanation:

  • d = m/V, where d is the density, m is the mass and V is the volume.
  • We have the mass m = 0.50 g, so we must get the volume V.
  • To get the volume of a gas, we apply the general gas law PV = nRT

P is the pressure in atm (P = 1.5 atm)

V is the volume in L (V = ??? L)

n is the number of moles in mole, n = m/Atomic mass, n = 0.50/12.0 = 0.416 mole.

R is the general gas constant (R = 0.082 L.atm/mol.K).

T is the temperature in K (T(K) = T(°C) + 273 = -20.0 + 273 = 253 K).

  • Then, V = nRT/P = (0.416 mol)(0.082 L.atm/mol.K)(253 K) / (1.5 atm) = 0.576 L.
  • Now, we can obtain the density; d = m/V = (0.50 g) / (0.576 L) = 0.867 g/L.
6 0
4 years ago
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