Answer:
The magnitude of the force exerted by the locomotive on the caboose is 3.08 N.
Explanation:
Given that,
Mass of a toy, m = 2.3 kg
Mass of caboose, m' = 1 kg
The frictional force of the track on the caboose is 0.48 N backward along the track.
The acceleration of train, ![a=2.6\ m/s^2](https://tex.z-dn.net/?f=a%3D2.6%5C%20m%2Fs%5E2)
The magnitude of the force exerted by the locomotive on the caboose is given by :
![F=m'a+f\\\\F=1\times 2.6+0.48\\\\F=3.08\ N](https://tex.z-dn.net/?f=F%3Dm%27a%2Bf%5C%5C%5C%5CF%3D1%5Ctimes%202.6%2B0.48%5C%5C%5C%5CF%3D3.08%5C%20N)
So, the magnitude of the force exerted by the locomotive on the caboose is 3.08 N.
Answer:
2.8 %
Explanation:
Power deliver by the cell = 4.2 x 10^-3 W
Power given to the cell = 0.15 W
The efficiency of the cell is defined as the ratio of power deliver by the cell to the power given to the cell.
So, the efficiency of the cell
= power deliver by the cell / power given to the cell
= ![\frac{4.2\times10^{-3}}{0.15}](https://tex.z-dn.net/?f=%5Cfrac%7B4.2%5Ctimes10%5E%7B-3%7D%7D%7B0.15%7D)
= 0.028
in percentage form = 0.028 x 100 % = 2.8 %
Thus, the efficiency of the photo voltaic cell is 2.8 %.
Answer:
D
Explanation:
correct me if I'm wrong on your answer and it's the right answer from my son
M/s is 860 your anser is 47miles
First blank - physical or chemical
Second blank - less usable
The second law of thermodynamics states that whenever energy is converted from one form to another in a(n) physical or chemical change, we end up with less usable energy than before.
If we think of a simple steam system, which relies on a coal or wood fire to create the steam, even if we make our best attempts at insulating and decreasing the amount of escape of heat, we will undoubtedly have less energy in the heated water or steam through the physical change of the wood or coal into heat energy to heat the water to create the steam, in each of these physical changes we lose energy.