Answer:
= 26.94 m/s
Explanation:
given,
angle of inclination = 30°
mass of the sleigh = 200 kg
coefficient of kinetic friction = 0.2
height of inclination = 10 m
pull force be = 5000 N
now,.
T - f_s - mg sin \theta = m aT−f
s
−mgsinθ=ma
T - \mu N - mg sin \theta = m aT−μN−mgsinθ=ma
T - \mu mg - mg sin \theta = m aT−μmg−mgsinθ=ma
a = \dfrac{T}{m} - \mu g - g sin \thetaa=
m
T
−μg−gsinθ
a = \dfrac{5000}{200} - \0.2\times 9.8 - 9.8 \times sin 30^0a=
200
5000
−\0.2×9.8−9.8×sin30
0
a = 18.14\ m/s^2a=18.14 m/s
2
L = \dfrac{10}{sin 30}L=
sin30
10
L = 20 m
v² = u² + 2 as
v² = 0 + 2 x 18.14 x 20
v = 26.94 m/s
Answer:
<u>C: Energy </u>
Explanation:
Waves can transfer energy over large distances.
Yes,it’s an object because it’s solid I think...
Given:
u=0 m/s
a=1.1 m/s^2
S=5 m
t=time it takes to run 5 m
Use the kinematics equation
S=ut+(1/2)at^2
=>
5=0*t+(1/2)1.1(t^2)
solve for t
t=sqrt(5*2/1.1)=3.015 seconds.
Answer:
<em>13 m/s²</em>
Explanation:
Mass of object = 200 Kg
Applied force = 2600 N
Acceleration = ?
Solution:
Definition:
The acceleration is rate of change of velocity of an object with respect to time.
Formula:
a = Δv/Δt
a = acceleration
Δv = change in velocity
Δt = change in time
Units:
The unit of acceleration is m.s⁻².
Acceleration can also be determine through following formula,
F = m × a
a = F/m (N = kgm/s²)
a = 2600 kgm/s² / 200 Kg
a = 13 m/s²