The sand will be filtered and separated from the water, the sand will stay in/on the filter paper and the water will pass through the filter paper into the flask.
True precise and accurate are the same thing
The molarity of the solution is calculated by dividing the number of moles of the solute, in moles, by the total volume of the solution, in liters.
The molar mass of calcium hydroxide, Ca(OH)2 is calculated below.
m = molar mass Ca + 2(molar mass O) + 2(molar mass H)
Substituting,
m = 40 g/mol + 2(16 g/mol) + 2(1 g/mol)
m = 74 g/mol
To get the number of moles Ca(OH)2 in 75.8 grams,
n = (75.8 grams)(1 / 74 g/mol) = 1.024 moles
The molarity, M, is therefore,
M = (1.024 moles Ca(OH)2) / (1.2 L)
M = 0.854 M
<em>Answer: 0.854 M</em>
Metals of Group 1 donate 1 electron from its ns orbital to form ionic bond, where n is the no. of its outermost shell.
Metals of Group 2<span> donate 2 electrons from its ns orbital to form ionic bond, where n is the no. </span>of its <span>outermost shell. </span>
<u>Answer:</u> The energy of the complex is
<u>Explanation:</u>
To calculate the energy of the complex, we use the equation given by Planck which is:
where,
= Wavelength of the complex = (Conversion factor: )
h = Planck's constant =
c = speed of light =
= Avogadro's number =
= energy of the complex
Putting values in above equation, we get:
Conversion factor used: 1 kJ = 1000 J
Hence, the energy of the complex is