Answer:
28,125 g
Explanation:
m(O₂) = 100 g
n(O₂) =M(O₂)/m(O₂)=32 gram per mole / 100 g = 0,32 mole
O₂ + 2H₂ ⇒ 2H₂O , n(H₂O) = 2 × n(O₂)
m(H₂O) = M(H₂O)/2 × n(O₂) = 18 grams per mole / 2 × 0,32 mole = 28,125 g
Saturated fatty acids are the type of fatty acids where all of them have single bonds. Their name comes from the fact that usually the second bond they have will be broken up and because of this each half of the bond can be saturated (attached to) with a hydrogen atom that can be available in near vicinity. It is worth noting that thhe fatty acids of fish and plants are mostly unsaturated (either mono-unsaturated or poly-unsaturated) while the fatty acids of animals are mostly saturated.
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Answer:
Electrolytes are substances that can ionize in water. They could be acids, bases or salts as long as they give ions when they dissolve in water.
Explanation:
- <em>Strong electrolytes</em> completely ionize when dissolved in water, leaving no neutral molecules. The strong electrolytes here are:<u> salt water</u>, <u>baking soda (NaHCO3) solution.</u>
- <em>Weak electrolytes</em> do not completely dissociate in solution, and hence have a low ionic yield. Examples of this would be<u> vinegar </u>and <u>bleach </u>(which could be sodium hypochlorite or chlorine, which are weakly dissociated).
- <em>Non-electrolytes </em>will remain as molecules and are not ionized in water at all. In this case, <u>sugar solution is a non-electrolytes</u>, even though sugar dissolves in water, but it remains as a whole molecule and not ions.
<h2>Solutions:</h2>
<u>Case a:</u> Finding pH for [H⁺] = 1.75 × 10⁻⁵ mol/L :
As we know pH is given as,
pH = -log [H⁺]
Putting value,
pH = -log [1.75 x 10⁻⁵]
pH = 4.75
<u>Case b:</u> Finding pH for [H⁺] = 6.50 × 10⁻¹⁰ mol/L :
As we know pH is given as,
pH = -log [H⁺]
Putting value,
pH = -log [6.50 × 10⁻¹⁰]
pH = 9.18
<u>Case c:</u> Finding pH for [H⁺] = 1.0 × 10⁻⁴ mol/L :
As we know pH is given as,
pH = -log [H⁺]
Putting value,
pH = -log [1.0 × 10⁻⁴]
pH = 4
<u>Case d:</u> Finding pH for [H⁺] = 1.50 × 10⁻⁵ mol/L :
As we know pH is given as,
pH = -log [H⁺]
Putting value,
pH = -log [1.50 × 10⁻⁵]
pH = 4.82
The answer is in the attachment below:
