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algol13
3 years ago
8

A student mixes chemicals A and B together and records the amount of time it takes for a color change to occur. The student repe

ats the process 5 more times each time changing the amount of chemical B used in the mixture. The independent variable in this experiment is the:
Chemistry
1 answer:
k0ka [10]3 years ago
8 0

Answer:

It is mentioned that the student is mixing chemicals A and B and observes the time taken for the color to change. However, in the experiment, it is noticed that the student has repeated the procedure five times and each time he or she is modifying the concentration of chemical B. Thus, it is clear that the concentration of chemical B is the independent variable in the experiment. An independent variable is illustrated as the variable, which is controlled or modified in the experiment.

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Answer:

<h2> a. 23.6</h2>

Explanation:

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3 years ago
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3 years ago
Calculate the pH of a 0.50 M HIO. The Ka of hypoiodic acid, HIO, is 2.3x10–11.0.305.325.479.474.80
never [62]

Answer:

pH = 5.47

Explanation:

The equilibrium that takes place is:

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Ka = \frac{[H+][IO-]}{[HIO]} = 2.3 * 10⁻¹¹

At equilibrium:

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<u>Replacing those values in the equation for Ka and solving for x:</u>

Ka=\frac{x^2}{0.5-x}=2.3*10^{-11} \\x^2=(2.3*10^{-11})(0.5-x)\\x^2=1.15*10^{-11}-2.3*10^{-11}x\\x^2+2.3*10^{-11}x-1.15*10^{-11}=0\\x=3.39*10^{-6}

Then [H⁺]=3.39 * 10⁻⁶, thus pH = 5.47

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3 years ago
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alex41 [277]

Answer:

Explanation:

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