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4 years ago

When two notes are played simultaneously creating a discordant sound it is called

1 answer:

4 0

A dissonance is an unstable tone combination ; it tension demands an onward motion to a stable chord, thus dissonant chords are active.

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An atom of element X has one more shell of electrons than an atom of beryllium, but it has one less valence electron than beryll

8090 [49]

Mg magnesium becuase one period down and one group to the side

7 0

3 years ago

Read 2 more answers

7. Nancy has a mass of 60 kg and sits on the very end of a 3.00 m long plank pivoted in the middle. How much torque must her co-

netineya [11]

Answer:

Torque = 882Nm

Explanation:

Torque = Mg×distance

But plank's is pivoted ,therefore distance=3/2=1.5m

Mass of Nancy=60jg

Acceleration due to gravity, g=9.8m/s^2

Torque= 60×9.8×1.5

Torque= 882Nm

6 0

3 years ago

A 1500-kg car traveling east with a speed of 25.0 m/s collides at an intersection with a 2500-kg van traveling north at a speed

IgorC [24]

Answer:

The direction and magnitude of velocity is 38.65° and 12.005 m/s

Explanation:

Given that,

Mass of car = 1500 kg

Speed of car = 25.0 m/s

Mass of van = 2500 kg

Speed of van =20.0 m/s

We need to calculate the velocity

Using conservation of energy

$m_{c}u_{i}+m_{v}u_{i}=(m_{c}+m_{v})v_{f}$

$1500(25i+0j)+2500(0+20j)=4000(v_{f})$

$v_{f}=\dfrac{1500\times25}{4000}i+\dfrac{1500\times20}{4000}j$

$v_{f}=9.375 i+7.5 j$

The magnitude of velocity

$|v_{f}|=\sqrt{(9.375)^2+(7.5)^2}$

$|v_{f}|=12.005\ m/s$

We need to calculate the direction

$\tan\theta=\dfrac{coefficient\ of\ j}{coefficient\ of\ i}$

$\tan\theta=\dfrac{7.5}{9.375}$

$\theta=\tan^{-1}0.8$

$\theta=38.65^{\circ}$

Hence, The direction and magnitude of velocity is 38.65° and 12.005 m/s.

3 0

4 years ago

Describe the motion of an object as it accelerates. IN YOUR OWN WORD!! ASAP

Pachacha [2.7K]

Answer:

The aceleration of an object is in the direction of the net force. If you push or pull an object in a particular direction, it accelerates in that direction. The aceleration has a magnitude directly proportional to the magnitude of the net force.

Explanation:

Hope this helps Plz mark brainliest

5 0

3 years ago

Un contenedor de 1800 N está en reposo sobre un plano inclinado a 28°, el coeficiente de fricción entre el contenedor y el plano

babunello [35]

Answer:

F = 1480.77N

Explanation:

In order to calculate the required force to push the container with a constant velocity, you take into account the the sum of force on the container is equal to zero. Furthermore, you have for an incline the following sum of forces:

$F-Wsin\alpha-F_r=0\\\\F-Wsin\alpha-N\mu cos\alpha=0\\\\F-Wsin\alpha-W\mu cos\alpha=0$ (1)

F: required force = ?

W: weight of the container = 1800N

N: normal force = weigth

α: angle of the incline = 28°

g: gravitational acceleration = 9.8m/s^2

μ: coefficient of friction = 0.4

You solve the equation (1) for F and replace the values of the other parameters:

$F=W(sin\alpha+\mu cos\alpha)\\\\F=(1800N)(sin28\°+(0.4)cos28\°)=1480.77N$

The required force to push the container for the incline with a constant velocity is 1480.77N

8 0

3 years ago