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azamat
3 years ago
12

An object accelerates from rest at a constant rate covering a distance of 18 meters in 3 seconds. What is its rate of accelerati

on?
Put your answer in this form:

X (m/s)/s
Physics
2 answers:
Neko [114]3 years ago
8 0

Answer:

4 m/s² or 4(m/s)/s

Explanation:

the equations of motion are

S= ut +½at²

v² = u²+ 2as

v = u + at

s = (u+v)/2 × t

From the parameters given

u = 0m/s this is because it starts from rest

Distance (s)  = 18m

Time (t)  = 3s

Based on this the first equation would be used

s = ut + ½at²

Input values

18 = 0×3 + ½ × a x 3²

18 = 0 + 9a/2

18 = 4.5a

Divide both sides by 4.5

a = 18 / 4.5 m/s²

a = 4 m/s² or 4(m/s)/s

I hope this was helpful, please mark as brainliest

ozzi3 years ago
4 0

Answer:

4

  1. 18*2=36
  2. 36/(3*3)=4
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Answer:

40 s

Explanation:

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Let t be the number of seconds after the second skater starts will the second skater overtake the first skater

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Similarly the distance traveled by the 2nd skater after t seconds is

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Since the 2nd skater catches up to the 1st one after 80 m behind, the distance traveled by the 2nd one must be 80m greater than the distance of the 1st skater

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The kinetic energy of an object depends on what?
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2 years ago
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Substitute V = Ed into the energy W.

W = 1/2 × ε A/d ×( Ed )^2

W = 1/2 × ε A/d × E^2 × d^2

d will cancel one of the ds

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W/V = 1/2 × ε E^2

Where Ad = volume V

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The permittivity of the material will be achieved by using the same formula

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2800 = 0.5 × ε × (18.9×10^6)^2

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ε = 2800/1.78×10^14

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k = 1.57×10^-11/8.84×10^-12

k = 1.776

k = 1.8 approximately

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