Vx=cos60(4)
x-component of velocity
<span>If you think about it, it makes a right triangle when you combine all the different types of forces together such as v, vx and vy. Then, you can use trigonometry and soh cah toa in order to figure out vx. </span>
I can see three different transitions here:
3 --> 1
3 --> 2
followed by
2 --> 1 .
So we should expect to see three different 'colors'
being emitted from this excited mob.
Answer:
Moment of inertia of the system is 289.088 kg.m^2
Explanation:
Given:
Mass of the platform which is a uniform disk = 129 kg
Radius of the disk rotating about vertical axis = 1.61 m
Mass of the person standing on platform = 65.7 kg
Distance from the center of platform = 1.07 m
Mass of the dog on the platform = 27.3 kg
Distance from center of platform = 1.31 m
We have to calculate the moment of inertia.
Formula:
MOI of disk = 
Moment of inertia of the person and the dog will be mr^2.
Where m and r are different for both the bodies.
So,
Moment of inertia 
of the system with respect to the axis yy.
⇒ 
⇒ 
⇒ 
⇒ 
The moment of inertia of the system is 289.088 kg.m^2
Answer:
<em>The distance of the light is 9.4608 x 10^25 m</em>
<em></em>
Explanation:
Time taken by the light = 10 billion years = 10 x 10^9 years
speed of light = 3 x 10^8 m/s
speed of light in m/years is = (3 x 10^8)/(60 x 60 x 24 x 365) = 9.4608 x 10^15 m/year
distance = speed x time
therefore, the distance of this light = 10 x 10^9 x 9.461 x 10^15 = <em>9.4608 x 10^25 m</em>
Answer:
Δx = 3.99 m
Explanation:
To determine distance, use kinetic energy
will make it short and easy.
KE=1/2mv2 and KE=Δxmgμ
Set the equations equal to each other
1/2mv2=Δxmgμ (Note: The masses cancel
)
1/2v2=Δxgμ Solve for Δx
where g=9.8
Δx=v2/(2gμ) Δx = 25 / (2 * 9.8 * 0.32) Δx = 3.99 m
Please let me know if its correct, if not report it so we can correct it.
