Question

An object accelerates from rest at a constant rate covering a distance of 18 meters in 3 seconds. What is its rate of acceleration?
Put your answer in this form:

X (m/s)/s

Answer 1

Answer:

4 m/s² or 4(m/s)/s

Explanation:

the equations of motion are

S= ut +½at²

v² = u²+ 2as

v = u + at

s = (u+v)/2 × t

From the parameters given

u = 0m/s this is because it starts from rest

Distance (s)  = 18m

Time (t)  = 3s

Based on this the first equation would be used

s = ut + ½at²

Input values

18 = 0×3 + ½ × a x 3²

18 = 0 + 9a/2

18 = 4.5a

Divide both sides by 4.5

a = 18 / 4.5 m/s²

a = 4 m/s² or 4(m/s)/s

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Answer 2

Answer:

4

1. 18*2=36
2. 36/(3*3)=4