Answer:
because the product of CuO contains 2 molecules so it is unbalanced
Explanation:
to balance it 2Cu+2O=4CuO now it is balanced
Moles of potassium permanganate = 0.0008
<h3>Further explanation </h3>
Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range
Reaction
5Na2C2O4(aq) + 2KMnO4(aq) + 8H2SO4(aq) ---> 2MnSO4(aq) + K2SO4(aq) + 5Na2SO4(aq) + 10CO2(g) + 8H2O(1)
The end point ⇒titrant and analyte moles equal
titrant : potassium permanganate-KMnO4
analyte : sodium oxalate - Na2C2O4
so moles of KMnO4 = moles of Na2C2O4
moles of Na2C2O4(mass = 0.2640 g, MW=134 g/mol) :
From equation, mol ratio Na2C2O4 : KMnO4 = 5 : 2, so mol KMnO4 :
Volume of the gas is 525 L.
<u>Explanation:</u>
It is given that the volume of the gas divided by the temperature is 1.75.
V/T = 1.75
As per the Charles law, volume is proportional to the temperature.
V ∝ T
V/T = constant
Now we have to find V, and T is given as 300 K.
So plugin the values as,
V/300 = 1.75
Rearranging the equation to get V as,
V = 1.75×300
= 525 L
Answer: 1. rock stone gase from developing the other difference
The enthalpy of the solution is <u>positive </u>and the entropy is <u>positive</u>.
Potassium trioxonitrate (V) KNO₃(s) is a strong oxidizing solid substance that when dissolved in water changes to aqueous solution.
In its aqueous solution state, the randomness of molecules increases as a result of that the entropy will also increase leading to the positive state of the entropy.
Similarly, provided that the solution becomes quite cold to the touch, the enthalpy is also in it positive state.
Therefore, we can conclude that the enthalpy of the solution is <u>positive </u>and the entropy is <u>positive</u>.
Learn more about Potassium trioxonitrate (V) KNO₃(s) here:
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