Answer:
8.946g NaHCO₃,
14.475g H₂O,
1.025g CH₃COO⁻Na⁺,
0.500g CO₂.
Explanation:
Baking soda (NaHCO₃) reacts with vinegar (CH₃COOH 5%) producing CH₃COO⁻Na⁺, H₂O and CO₂, thus:
NaHCO₃ + CH₃COOH → CH₃COO⁻Na⁺ + H₂O + CO₂
10g of NaHCO₃ are:
10g × (1mol / 84g) = 0.119 moles NaHCO₃
Moles of CH₃COOH in 15g of vinegar are:
15g vinegar × 5% = 0.75g CH₃COOH × (1mol / 60g) = 0.0125moles CH₃ COOH
After reaction, moles of NaHCO₃ that remains are:
0.119mol - 0.0125mol = <em>0.1065 moles NaHCO₃</em>
In mass:
0.1065mol ₓ (84g / 1mol) = <em>8.946g NaHCO₃</em>
Acetic acid reacts completely producing 0.0125moles of CH₃COO⁻Na⁺, water and CO₂. In mass:
CH₃COO⁻Na⁺ = 0.0125mol ₓ (82.03g / 1mol) = <em>1.025g CH₃COO⁻Na⁺</em>
H₂O = 0.0125mol ₓ (18.01g / 1mol) = <em>0.225g H₂O</em>
CO₂ = 0.0125mol ₓ (40g / 1mol) = <em>0.500g CO₂</em>
Now, 95% of vinegar is water (Doesn't react), that is:
15g × 95% = 14.25g H₂O. Total mass of water is:
14.25g + 0.225g = <em>14.475g H₂O</em>
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Total mass is:
8.946g + 14.475g H₂O + 1.025g + 0.500g ≈ 25g. The same than initial mass following law of conservation of matter.
