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schepotkina [342]
3 years ago
9

Drag the words in the left-hand column to the appropriate blanks in the right-hand column. Reset Help Newton's first law of moti

on the orbit of each planet about the Sun is an ellipse with the Sun at one focus. Newton's second law of for any force, there is an equal and opposite reaction force. motion Newton's third law of motion a planet moves faster in the part of its orbit nearer the Sun and slower when farther from the Sun, sweeping out equal areas in equal times. Kepler's first law of planetary motion force = mass x acceleration Kepler's second law of planetary motion more distant planets orbit the Sun at slower average speeds, obeying the precise Kepler's third law of mathematical relationship p2 a3 planetary motion an object moves at constant velocity if there is no net force acting upon it
Physics
1 answer:
Tom [10]3 years ago
7 0

Explanation:

In this case, we need to write correct statement about the topics :

1. Kepler's first law of planetary motion = the orbit of each planet about the Sun is an ellipse with the Sun at one focus.

2. Newton's third law of motion = for any force, there is an equal and opposite reaction force.

3. Kepler's second law of planetary motion = a planet moves faster in the part of its orbit nearer the Sun and slower when farther from the Sun, sweeping out equal areas in equal times.

4. Newton's second law of motion = force = mass x acceleration

5. Kepler's third law = more distant planets orbit the Sun at slower average speeds obeying the mathematical relation, p^2=a^3

6. Newton's second law of motion = an object moves at constant velocity if there is no net force acting upon it

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gulaghasi [49]
A compound optical microscope or just a optical microscope is a microscope that uses light and has more than one lens.
4 0
3 years ago
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A marshmallow is dropped from a 5.71 meter high pedestrian bridge, and 0.921 seconds later, it lands right on the head of an uns
Natalka [10]

let the height of the person with marshmallow on her head be "h"

consider the motion of the marshmallow after it is dropped from bridge.

Y₀ = initial position of the marshmallow above the ground = 5.71 m

Y = final position of marshmallow on head of person = h

v₀ = initial velocity of the marshmallow = 0 m/s

a = acceleration due to gravity = - 9.8 m/s²

t = time of travel for marshmallow = 0.921 sec

Using the kinematics equation

Y = Y₀ + v₀ t + (0.5) a t²

inserting the values

h = 5.71 + 0 (0.921) + (0.5) (-9.8) (0.921)²

h = 5.71 - 4.16

h = 1.55 m

5 0
3 years ago
Peter’s body supplies a force of 500 N to run up a 10-m hill in 10 s. How much power is involved in Peter’s run up the hill? Exp
shutvik [7]

Answer: 500 Watts

Explanation:

Power P is the speed with which work W is done. Its unit is Watts (W), being 1 W=\frac{1 Joule}{1 s}.

Power is mathematically expressed as:

P=\frac{W}{t} (1)

Where t is the time during which work W  is performed.

On the other hand, the Work W done by a Force F refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.  It is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter (1J=(1N)(1m)=Nm  ).

When the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:  

W=(F)(d) (2)

In this case, we have the following data:

F=500 N

d=10 m

t=10 s

So, let's calculate the work done by Peter and then find how much power is involved:

From (2):

W=(500 N)(10 m) (3)

W=5000 J (4)

Substituting (4) in (1):

P=\frac{5000 J}{10 s} (5)

Finally:

P=500 W

3 0
3 years ago
Two charged particles are placed 2.0 meters apart. The first charge is +2.0 E-6 C, and the second charge is +4.0 E-6 C. What is
ipn [44]
F = kq1q2/r^2 

<span>q1 is first charge </span>
<span>q2 is second charge </span>
<span>k is 9 E9 </span>
<span>r is distance between them </span>

<span>F = (9E9)(2 E-6)(4 E-6)/2^2 = 0.018 N </span>

<span>A postive answer indicates a repulsive force</span>
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Can i get brainliest . i think it was used as a way of communication.
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