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Komok [63]
3 years ago
6

Protons have a __________ charge

Physics
1 answer:
denis23 [38]3 years ago
4 0

Protons have a positive charge.

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Constants Part A wo charged dust particles exert a force of 7.5x102 N n each other What will be the force if they are moved so t
alexandr1967 [171]

Answer:

New force, F'=48\times 10^3\ N

Explanation:

It is given that,

Force acting between two charged particles, F=7.5\times 10^2\ N

We need to find the force if they are moved so they are only one-eighth as far apart.

The force between two charged particles separated at a distance of r is given by :

F=k\dfrac{q_1q_2}{r^2}............(1)

If the charges are one-eighth as far apart then, r' =(1/8)r and new force is given by :

F'=k\dfrac{q_1q_2}{(\dfrac{r}{8})^2}..........(2)

Dividing equation (1) and (2) :

\dfrac{F}{F'}=\dfrac{1}{64}

F'=7.5\times 10^2\ N\times 64

F' = 48000 N

or

F'=48\times 10^3\ N

Hence, this is the required solution.

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3 years ago
Which of the following is the SI unit for volume
Katarina [22]
Meters for mass kilograms for volume cubic meters for density kilograms per cubic meter
3 0
3 years ago
Dimension of density <br>​
Rom4ik [11]

Answer:

See the explanation below.

Explanation:

We know that density is defined as the relationship between mass and volume.

Ro = m/V

where:

m = mass [kg]

V = volume [m³]

Therefore Ro is given in:

[kg/m^{3} ]

8 0
2 years ago
Calculate the maximal friction force for a parked car between the rubber tires and a wet street. Assume the car’s mass is 1600 k
NikAS [45]

Answer:

Fr=12544N

Explanation:

1. Find the equation of eht maximal friction force:

The maximal friction force is given by the equation Fr=usmg, where μs is the static friction coefficient, m is the car´s mass and g is the gravitational force.

2. Replace values in the equation to find the answer:

Fr=0.8*1600kg*9.8\frac{m}{s^{2}}

Fr=12544N

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3 years ago
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I think the answer is
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