In the game of billiards, all the balls have approximately the same mass, about 0.17 kg. In the figure, the cue ball strikes ano
ther ball such that it follows the path shown. The other ball has a speed of 1.5 m/s immediately after the collision. What is the speed (in m/s) of the cue ball after the collision?
1 answer:
Answer:
v = 2.6 m/s
Explanation:
The question is incomplete because the diagram is not given in the question.
The diagram of this question is attached below.
According to the law of conversation of momentum.
mv(initial) = mv(final)
We can see in the diagram that:
mv(initial) = 3 × 0.17
mv(final) = mv₁(final) + mv₂(final)
Consider only the horizontal components of velocities, to compare them to initial velocity.
mv(final) = mv₁(final) + mv₂(final)
0.17 × 3 = (0.17)(v)(cos 30) + (0.17)(1.5)(cos 60)
0.51 = 0.1472v + 0.1275
0.3825 = 0.1472v
v = 2.6 m/s
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Answer:
a.) a = 0 ms⁻²
b.) a = 9.58 ms⁻²
c.) a = 7.67 ms⁻²
Explanation:
a.)
Acceleration (a) is defined as the time rate of change of velocity
Given data
Final velocity = v₂ = 0 m/s
Initial velocity = v ₁ = 0 m/s
As the space shuttle remain at rest for the first 2 minutes i.e there is no change in velocity so,
a = 0 ms⁻²
b.)
Given data
As the space shuttle start from rest, So initial velocity is zero
Initial velocity = v₁ = 0 ms⁻¹
Final velocity = v₂ = 4600 ms⁻¹
Time = t = 8 min = 480 s
By the definition of Acceleration (a)
a = 9.58 ms⁻²
c.)
Given data
As the space shuttle is at rest for first 2 min then start moving, So initial velocity is zero
Initial velocity = v₁ = 0 ms⁻¹
Final velocity = v₂ = 4600 ms⁻¹
Time = t = 10 min = 600 s
By the definition of Acceleration (a)
a = 7.67 ms⁻²
<h2>Answer: x=125m, y=48.308m</h2>
Explanation:
This situation is a good example of the projectile motion or parabolic motion, in which we have two components: x-component and y-component. Being their main equations to find the position as follows:
x-component:
(1)
Where:
is the projectile's initial speed
is the angle
is the time since the projectile is launched until it strikes the target
is the final horizontal position of the projectile (the value we want to find)
y-component:
(2)
Where:
is the initial height of the projectile (we are told it was launched at ground level)
is the final height of the projectile (the value we want to find)
is the acceleration due gravity
Having this clear, let's begin with x (1):
(3)
(4) This is the horizontal final position of the projectile
For y (2):
(5)
(6) This is the vertical final position of the projectile
Answer:
Explanation:
We are given that
Gravitational force=
r=0,U(0)=0
We know that
Gravitational potential energy=
Substitute r=0 ,U(0)=0
Substitute the value