All categories

3 years ago

PLZ RESPONDE QUICKLY MY EDUCATION IS ON THE LINE

Chemistry

1 answer:

lyudmila [28]3 years ago

6 0

Answer:

N= PV/RT (temperature in kelvin); ( r is .0821 when pressure is in atm & r is 8.314 when pressure is in Kpa)

2.00 = P x 10.0/ .0821 x 300

after solving i got 4.926 atm

You might be interested in

Raising the concentration of hydronium ions, H3O+, in a solution will result in the pH level _________.

algol [13]

Answer:B) Going Down

Explanation:

The higher the concentration of hydro in ions in a solution, the more acidic it is, and the lower the pH is.

(I just answered the question on USA TP!)

3 0

3 years ago

_ g of potassium reacts with 16 g of oxygen to produce 94 g of potassium oxide

natali 33 [55]

Due to the law of conservation of mass, _g K + 16g O=94g KO.
So, 94-16=78
78 is your answer

5 0

4 years ago

Read 2 more answers

When someone’s immune system overreacts to something harmless it’s called:

ruslelena [56]

I feel like it would be c

5 0

4 years ago

Read 2 more answers

) B5H9(l) is a colorless liquid that will explode when exposed to oxygen. How much heat is released when 0.211 mol of B5H9 react

Tom [10]

<u>Answer:</u> The amount of heat released when 0.211 moles of $B_5H_9(l)$ reacts is 554.8 kJ

<u>Explanation:</u>

The chemical equation for the reaction of $B_5H_9$ with oxygen gas follows:

$2B_5H_9(l)+12O_2(g)\rightarrow 5B_2O_3(s)+9H_2O(l)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(5\times \Delta H_f_{(B_2O_3(s))})+(9\times \Delta H_f_{(H_2O(l))})]-[(2\times \Delta H_f_{(B_5H_9(l))})+(12\times \Delta H_f_{(O_2(g))})]$

We are given:

$\Delta H_f_{(H_2O(l))}=-285.4kJ/mol\\\Delta H_f_{(B_2O_3(s))}=-1272kJ/mol\\\Delta H_f_{(B_5H_9(l))}=73.2kJ/mol\\\Delta H_f_{(O_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(2\times (-1272))+(9\times (-285.4))]-[(2\times (73.2))+(12\times (0))]\\\\\Delta H_{rxn}=-5259kJ$

To calculate the amount of heat released for the given amount of $B_5H_9(l)$ , we use unitary method, we get:

When 2 moles of $B_5H_9(l)$ reacts, the amount of heat released is 5259 kJ

So, when 0.211 moles of $B_5H_9(l)$ will react, the amount of heat released will be = $\frac{5259}{2}\times 0.211=554.8kJ$

Hence, the amount of heat released when 0.211 moles of $B_5H_9(l)$ reacts is 554.8 kJ

7 0

3 years ago

Write a chemical equation showing how this is an acid according to the arrhenius definition. express your answer as a balanced c

Alik [6]

According to Arrhenius theory, acid is a substance that releases H⁺ ions when dissolved in water.

In order to apply this theory, the substance must be soluble in water.

H₂SO₄ is highly soluble in water. It undergoes following dissociation reaction when dissolved in water.

$H_{2}SO_{4}(aq)\overset{H_{2}O}{\rightarrow} 2H^{+}(aq)+ SO_{4}^{2-}(aq)$

From the above equation, we can see that H₂SO₄ forms 2 H⁺ ions when dissolved in water. Therefore it behaves as an acid according to Arrhenius theory.

7 0

3 years ago