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Usimov [2.4K]
4 years ago
9

a diver is standing on the diving board. the diver has a mass of 85.0kg and has a gravitational potential emergy of 2.50x103 j s

tanding on the diving board. determine how high the diver is above the water surface
Physics
1 answer:
amid [387]4 years ago
5 0

Answer:

<h2>3.00m high</h2>

Explanation:

Gravitational potential energy of the diver is expressed mathematically as

P = mgh

m = mass of the diver (in kg)

g = acceleration due to gravity (in m/s²)

h = the height of the diver above the water surface.

Given m = 85.0kg, g = 9,8m/s² and P = 2.50x10³ Joules, wecan determine how high the diver is above the water surface bu substituting the given values into the formula;

h = P/mg

h = 2.50x10³/85*9.8

h = 2500/833

h ≈ 3.00m

The diver is 3.00m above the water surface.

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A 1.2 kg basketball is thrown upwards. What is the potential energy of the basketball at the top of its path if it reaches a hei
Dahasolnce [82]

Answer:

Answer is 183.6 J

Explanation:

Using the Physics reference sheet the formula for Potential energy is

(mass) x (gravity) x (height)

Mass= 1.2

Gravity I used is 9.81 (use 10 to get the answer most schools use)

Height= 15.6

5 0
3 years ago
For the winter, a duck flies 10.0 m/s due south against a gust of wind with a velocity of 2.5 m/s. What is the resultant velocit
maria [59]

Answer:

c. 7.5 m/s south

Explanation:

<u>Given the following data;</u>

Velocity of duck = 10m/s due South

Velocity of wind = 2.5m/s

To find the resultant velocity;

Since we know that the duck is flying against a gust of wind, we would have to subtract the velocity of the gust of wind from that of the duck.

This ultimately implies that, the gust of wind (headwind) would decrease the resulting velocity of the duck because it approaches the duck from the front.

Resultant velocity, /V/ = 10 - 2.5

Resultant velocity, /V/ = 7.5m/s South.

<em>Therefore, the resultant velocity of the duck is 7.5m/s south. </em>

6 0
3 years ago
Chapter 38, Problem 001
Norma-Jean [14]

Answer:

a) \lambda=2.95x10^{-6}m

b) infrared region

Explanation:

Photon energy is the "energy carried by a single photon. This amount of energy is directly proportional to the photon's electromagnetic frequency and is inversely proportional to the wavelength. If we have higher the photon's frequency then we have higher its energy. Equivalently, with longer the photon's wavelength, we have lower energy".

Part a

Is provide that the smallest amount of energy that is needed to dissociate a molecule of a material on this case 0.42eV. We know that the energy of the photon is equal to:

E=hf

Where h is the Planck's Constant. By the other hand the know that c=f\lambda and if we solve for f we have:

f=\frac{c}{\lambda}

If we replace the last equation into the E formula we got:

E=h\frac{c}{\lambda}

And if we solve for \lambda we got:

\lambda =\frac{hc}{E}

Using the value of the constant h=4.136x10^{-15} eVs we have this:

\lambda=\frac{4.136x10^{15}eVs (3x10^8 \frac{m}{s})}{0.42eV}=2.95x10^{-6}m

\lambda=2.95x10^{-6}m

Part b

If we see the figure attached, with the red arrow, the value for the wavelenght obtained from part a) is on the infrared region, since is in the order of 10^{-6}m

4 0
3 years ago
What are those tiny things that you plant underground to grow plants?
guajiro [1.7K]
The answer is seeds the thing that with proper care grows plants
8 0
3 years ago
What is time taken by the stone ?
SSSSS [86.1K]

The time taken by the stone to hit the ground would be 5.12 seconds.

<h3>What are the three equations of motion?</h3>

There are three equations of motion given by  Newton

The first equation is given as follows

v = u + at

the second equation is given as follows

S = ut + 1/2×a×t²

the third equation is given as follows

v² - u² = 2×a×s

Keep in mind that these calculations only apply to uniform acceleration.

As given in the problem, a stone is dropped from the helicopter which is ascending at the speed of 19.6 m/s

height(S) = 156.8 meters

initial velocity(u) = -19.6 m/s

acceleration(a) = 9.81 m/s²

By using the second equation of motion given by newton

S = ut + 1/2at²

S = 156.8m ,u= -19.6 m/s , a= 9.81 m/s² and t =? seconds

156.8= -19.6t + 9.81t²

t = 5.12 seconds

Thus, the time taken by the stone to hit the ground would be 5.12 seconds.

Learn more about equations of motion from here,

brainly.com/question/5955789

#SPJ1

8 0
2 years ago
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