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Usimov [2.4K]
3 years ago
9

a diver is standing on the diving board. the diver has a mass of 85.0kg and has a gravitational potential emergy of 2.50x103 j s

tanding on the diving board. determine how high the diver is above the water surface
Physics
1 answer:
amid [387]3 years ago
5 0

Answer:

<h2>3.00m high</h2>

Explanation:

Gravitational potential energy of the diver is expressed mathematically as

P = mgh

m = mass of the diver (in kg)

g = acceleration due to gravity (in m/s²)

h = the height of the diver above the water surface.

Given m = 85.0kg, g = 9,8m/s² and P = 2.50x10³ Joules, wecan determine how high the diver is above the water surface bu substituting the given values into the formula;

h = P/mg

h = 2.50x10³/85*9.8

h = 2500/833

h ≈ 3.00m

The diver is 3.00m above the water surface.

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1) See three Kepler laws below

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There are three Kepler's law of planetary motion:

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2a)

To solve the problem, we have to write the equation of motions for each block along the direction parallel to the incline.

For the block on the right, we have:

M g sin \theta - T = Ma (1)

where

Mg sin \theta is the component of the weight of the block parallel to the incline, with

M = 8.0 kg (mass of the block)

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a = acceleration of the block

For the block on the left, we have similarly

T-mg sin \theta = ma (2)

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m = 3.5 kg (mass of the block)

\theta=35^{\circ}

From (2) we get

T=mg sin \theta + ma

Substituting into (1),

M g sin \theta - mg sin \theta - ma = Ma

Solving for a,

a=\frac{M-m}{M+m}g sin \theta=\frac{8.0-3.5}{8.0+3.5}(9.8)(sin 35^{\circ})=2.2 m/s^2

2b)

The tension in the string can be calculated using the equation

T=mg sin \theta + ma

where

m = 3.5 kg (mass of lighter block)

g=9.8 m/s^2

\theta=35^{\circ}

a=2.2 m/s^2 (acceleration found in part 2)

Substituting,

T=(3.5)(9.8)(sin 35^{\circ}) +(3.5)(2.2)=27.4 N

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The kinetic energy of an object is the energy due to its motion. It is calculated as

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m is the mass of the object

v is its speed

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m is the mass of the object

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3b)

The kinetic energy of an object is given by

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m is the mass of the object

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m = 500 g = 0.5 kg

v = 3 m/s

Substituting, we find its kinetic energy:

K=\frac{1}{2}(0.5)(3)^2=2.25 J

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