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fenix001 [56]
3 years ago
10

Below is a diagram of a weight on a spring. When the weight is pulled down and then released, the spring compresses and expands.

Each position indicates a different point in time.
Which of the following statements is true?
a
In all four positions, mechanical energy is 0 J.
b
The elastic potential energy of the spring at Position 2 is converted to kinetic energy.
c
The chemical potential energy of the spring is greatest at Position 4.
d
In all four positions, the gravitational potential energy of the spring is the same.

Physics
1 answer:
mrs_skeptik [129]3 years ago
3 0

Answer:

B.

Explanation:

The elastic potential energy of the spriy at position 2 is converted to kinetic energy.

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A runner runs 10 miles in 1 hour. how far could they run in 2 hours in m/s?
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Answer:

4.47 m/s.

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10 mph -----------------------?

= 4.47 m/s

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Read 2 more answers
A single loop of nickel wire, lying flat in a plane, has an area of 7.40 cm^2 and a resistance of 2.40 Ω. A uniform magnetic fie
ale4655 [162]

Explanation:

It is given that,

Area of nickel wire, A=7.4\ cm^2=7.4\times 10^{-4}\ m^2

Resistance of the wire, R = 2.4 ohms

Initial value of magnetic field, B_1=0.5\ T

Final magnetic field, B_2=3\ T

Time, t = 1.12 s

Let I is the induced current in the loop of wire over this time. Te emf induced in the wire is given by Faraday's law as :

\epsilon=-\dfrac{d\phi}{dt}

\epsilon=-\dfrac{d(BA)}{dt}

\epsilon=-A\dfrac{d(B)}{dt}

\epsilon=-A\dfrac{B_2-B_1}{t}

\epsilon=-7.4\times 10^{-4}\times \dfrac{3-0.5}{1.12}

\epsilon=1.65\times 10^{-3}\ V

Induced current in the loop of wire is given by :

I=\dfrac{\epsilon}{R}

I=\dfrac{1.65\times 10^{-3}}{2.4}

I=6.87\times 10^{-4}\ A

So, the induced current in the loop of wire over this time is 6.87\times 10^{-4}\ A. Hence, this is the required solution.

7 0
3 years ago
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