Answer:
F = 3.2 x 10⁻⁵ N
Explanation:
The gravitational force of attraction between the two objects is given by Newton's Gravitational law through the following formula:
where,
F = gravitational force = ?
G = Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²
m₁ = mass of object 1 = 235 kg
m₂ = mass of object 2 = 1.37 x 10¹² kg
r = distance between objects = 2.59 x 10⁴ m
Therefore,
<u>F = 3.2 x 10⁻⁵ N</u>
The verb you want is 'Calculate'.
Possible terminal voltages are 6 - 1.5 =4.5 V or 6+1.5 = 7.5 V.
Voltage is the pressure from an electrical circuit's power supply that pushes charged electrons (present-day) thru an undertaking loop, enabling them to do work that includes illuminating a light. In quick, voltage = stress, and it's far measured in volts (V).
There are styles of voltage, DC voltage, and AC voltage. The DC voltage (direct modern-day voltage) usually has the same polarity (positive or poor), which includes a battery. The AC voltage (alternating current voltage) alternates between nice and bad.
Voltage, electric-powered capacity difference, electric-powered stress, or electric-powered anxiety is the difference in electric-powered capacity among points, which is defined as the work needed in step with a unit of charge to move a take a look at a rate between the two factors.
Learn more about voltage here brainly.com/question/14883923
#SPJ4
Within the system of the same star, the period of a planet's orbit is
proportional to the 3/2 power of its distance from the central body.
(Kepler's empirical third law of planetary motion, promoted to being
etched in stone by Newton's gravitation.)
(4) ^ 3/2 = <em>8 times</em> as long.
Answer:
Mass of methane takne = 1.5g
moles of methane used = masss / molar mass = 1.5 / 16 = 0.094 moles
mass of water = 1000 g
Initial temperature of water = 25 C
final temperature = 37 C
specific heat of water = 4.184 J /g C
1) Heat absorbed by water = q =m• C• ΔT = 1000 X 4.184 x (37-25) = 50208 Joules
2) Heat absorbed by calorimeter = Heat capacity X ΔT = 695 X (37-25) = 8340 J
3) Total heat of combustion = heat absorbed by water + calorimeter = 50208 + 8340 = 58548 Joules
This heat is released by 0.094 moles of methane
So heat released by one mole of methane =
- 622851.06 Joules = 622.85 kJ / mole
4) standard enthalpy of combustion = -882 kJ / mole
Error = (882-622.85) X 100 / 882 = 24.84 %