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Gala2k [10]
4 years ago
7

Can you help me with this.

Mathematics
1 answer:
Olin [163]4 years ago
5 0

Answer:

You would basically expand all the equations!

1. 7(4z+8b) is equal to 28z+56b.

2. 8(2x+3^2) is equal to 16x+72

3. 4(r+r+r+r) is equal to 4r+4r+4r+4r

4. 9(3+8x) is equal to 27+72x

5. 4^2(3+6f) is equal to 48+96t

6. (t+t+t)/4 is equal to t/4+t/4+t/4

7. 2(4s^3+2) is equal to 8s^3+4

8. 30(3x+4) is equal to 90x+120

9. 6(5a+9b) is equal to 30a+54b

10. 9(3x+5^4) is equal to 27x+5625

11. 7(c+c+c) is equal to 7c+7c+7c

12. 9(2+7f) is equal to 18+63f

13. 7^5(4g-8d) is equal to 67228g-134456d

Step-by-step explanation:

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Zip codes for the Houston area are five digit numbers with 7 as the first 2 digits of each zip code. The third digit can be 0, 3
djyliett [7]

Answer:

There are 400 possible zip codes in the Houston area

Step-by-step explanation:

Here, we want to calculate the possible number of zip codes in the Houston area

We have 5 digits to form

77 is the first two digits ( this is fixed)

For the third digit, we are selecting 1 number out of 0,3,4 or 5

This means 4 C 1

The remaining digits can be any digits

We have 0-9, a total of 10 digits

The first will be 10 C 1 and the second last digit too is 10 C 1

So the number of possible zip codes will be;

4 C 1 * 10 C 1 * 10 C 1

= 4 * 10 * 10 = 400 possible zip codes

6 0
3 years ago
Karl is purchasing a $205,000 home with a 30-year mortgage at 5.5%. Because he is not making a down payment, PMI in the amount o
Rina8888 [55]
$421,369.20 , I just had this question on Apex.

6 0
3 years ago
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Which expressions are equivalent?
Phoenix [80]

im pretty sure it's the first option.

6 0
4 years ago
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The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with an average weight of 5
Lisa [10]

Answer: 0.4987

Step-by-step explanation:

Given : The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with

Mean : \mu=5\text { lbs}

Standard deviation : \sigma= 2\text{ lbs}

Let X be the random variable that represents the weight of randomly selected student .

Z score : z=\dfrac{x-\mu}{\sigma}

For x = 5 lbs

z=\dfrac{5-5}{2}=0

For x = 11 lbs

z=\dfrac{11-5}{2}=3

By using the standard normal distribution table ,  the probability that the weight of the newborn baby boy will be between 5 lbs and 11 lbs :-

P(5

Hence, the probability that the weight of the newborn baby boy will be between 5 lbs and 11 lbs =0.4987

5 0
3 years ago
40/396 simplified can you help
Elena-2011 [213]

Answer:

10/99

Step-by-step explanation:

40/396

40÷4/396÷4

10/99

3 0
3 years ago
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