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3 years ago

Can you help me with this.

Mathematics

1 answer:

Olin [163]3 years ago

5 0

Answer:

You would basically expand all the equations!

1. 7(4z+8b) is equal to 28z+56b.

2. 8(2x+3^2) is equal to 16x+72

3. 4(r+r+r+r) is equal to 4r+4r+4r+4r

4. 9(3+8x) is equal to 27+72x

5. 4^2(3+6f) is equal to 48+96t

6. (t+t+t)/4 is equal to t/4+t/4+t/4

7. 2(4s^3+2) is equal to 8s^3+4

8. 30(3x+4) is equal to 90x+120

9. 6(5a+9b) is equal to 30a+54b

10. 9(3x+5^4) is equal to 27x+5625

11. 7(c+c+c) is equal to 7c+7c+7c

12. 9(2+7f) is equal to 18+63f

13. 7^5(4g-8d) is equal to 67228g-134456d

Step-by-step explanation:

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A carpenter is making a rectangular form for a concrete pad she wants the length of the path to be 11 feet more than the width o

Basile [38]

Answer:

Length = 16 or -5 feet.

Width = 5 or -16 feet.

Step-by-step explanation:

Let the length of the concrete pad = l

Let the width of the concrete pad = w

Given the following data;

Area of concrete pad, a = 80ft²

Translating the word problem into an algebraic equation, we have;

$l = 11 + w$

We know that, the area of rectangle, A = length * width

$A = l*w$

Substituting the values into the equation, we have;

$80 = (11 + w)w$

Expanding the bracket, we have;

$80 = 11w + w^{2}$

$w^{2} + 11w - 80 = 0$

*Solving the quadratic equation by using factorization method*

$w^{2} + 16w - 5w - 80 = 0$

$w(w + 16) - 5(w + 16) = 0$

$(w - 5)(w + 16) = 0$

Width, w = 5 feet or w = -16 feet.

Therefore, the width of the concrete pad is 5 feet or -16 feet.

To find its length, l;

$l = 11 + w$

When w = 5 feet

$l = 11 + 5$

Length, l = 16 feet

When w = - 16 feet

$l = 11 + (-16)$

$l = 11 - 16$

Length, l = -5 feet.

Hence, the dimensions of the concrete pad is 16 by 5 feet or -5 by -16 feet.

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2 years ago

What is the Y-intercept of the graph of the linear function? What is the slope?

xeze [42]

Answer:

The Y intercept is -5 and the slope is -5/2

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1 year ago

Nguyen was climbing a cliff. He stopped for a snack. After that, he

Yuki888 [10]

He traveled 20 feet after his snack

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2 years ago

4- What are the different waysto solve a quadratic? List examples of each

TiliK225 [7]

I know of two ways to solve quadratic equations. The first is through factoring. Let us take the example (x^2)+2x+1=0. We can factor this equation out and the factors would be (x+1)(x+1)=0. To solve for the roots, we equate each factor to 0, that is

x+1=0; x+1=0

In this case, the factors are the same so the root of the equation is

x=1.

The other way is to use the quadratic formula. The quadratic formula is given as [-b(+-)sqrt(b^2-4ac)]/2a where, using our sample equation above, a=1, b=2 and c=1. Substitute these to the formula, and you will get the same answer as the method above.

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2 years ago

I don’t understand, please help! Solve m=p/2-n for n.

belka [17]

Answer: n=p/2-m

Step-by-step explanation:

m=p/2-n (1)

Add n to both sides of the equation (1)

m+n=p/2-n+n => m+n=p/2 (2)

Subtract m from both sides of the equation (2)

m-m+n=p/2-m => n=p/2-m

6 0

2 years ago