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3 years ago

A number cube with the numbers 1 through 6 is rolled.

Mathematics

1 answer:

olchik [2.2K]3 years ago

6 0

Answer:

Step-by-step explanation:

Given that, we have a number cube label 1,2,3,4,5 and 6.

Then, the sample space is

S= {1, 2, 3, 4, 5, 6}

The probability of rolling a number different from 9?

Since we don't have 9 in the sample space, then the probability of rolling a number different from 9 will be the have 1,2,3,4,5 and 6 as the outcome

Then,

Pr(rolling number different from 9) = 6 / 6 = 1

Pr(rolling number different from 9) = 1.

The second option is correct.

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a ball is thrown straight up from the top of a 128 foot tall building with an initial speed of 32 feet per second. the height of

STatiana [176]

Factoring, you have
h(t) = -16(t^2 -2 -8) = -16(t -4)(t +2)

The ball hits the ground when h(t) = 0, so
0 = -16(t -4)(t +2)
t = 4 or -2

The positive solution is the one of interest.
It will take 4 seconds for the ball to hit the ground.

6 0

3 years ago

If tailia had 56 apples, her friend gave her 4, and her other friend gave her as many that added at 64 in today. How many apples

densk [106]

<h2><u>D:</u></h2><h2><em /></h2><h2><em>The awnser is </em><u><em>4</em></u><em>!! Hope this helps!! <3</em></h2>

3 0

3 years ago

Read 2 more answers

Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan

Lunna [17]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41

Alternate Hypothesis, $H_A$ : $\mu$ > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let $\mu$ = <u><em>mean sunspot activity during the Spanish colonial period.</em></u>

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41 {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, $H_A$ : $\mu$ > 41 {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean = 47

σ = population standard deviation = 35

n = sample of periods from Spanish colonial times = 40

So, <em><u>the test statistics</u></em> = $\frac{47-41}{\frac{35}{\sqrt{40} } }$

= 1.08

(b) The value of z test statistics is 1.08.

(c) <u>Now, the P-value of the test statistics is given by;</u>

P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

= 1 - 0.8599 = <u>0.1401</u>

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0

3 years ago

On march 24, 1989, the exxon valdez oil tanker ran aground and leaked millions of gallons of oil into prince william sound. the

Alja [10]

hours did it take for oil to cover the area = 592

The correct option is B.

<h3>What is geometrical figure?</h3>

Geometrical shapes are the shapes that depict the shapes of various items. Various figures have two dimensions, while others have three. Only the x and y axes are used for two-dimensional figures, whereas the x, y, and z axes are used for three-dimensional shapes.

<h3>According to the given information:</h3>

Given,

Area = 11000m²

Radius = .10m/h

We know the area of the circle:

Area = πr²

The relation between parameter:

Area = πr²

11000 = 3.14 * (0.10t)²

Dividing both side by 3.14

11000/3.14 = (3.14 * (0.10t)²)/3.14

by solving this we get:

(.10t)² = 3503.184

.10t = 59.187

dividing both side by 0.10

t = 59.187/.10

t = 591.877

t = 592

hours did it take for oil to cover the area = 592

To know more about geometrical figure visit:

brainly.com/question/17321335

#SPJ4

4 0

1 year ago

Maria y juan deben realizar el mapamundi en medio pliego de cartulina para la tarea de sociales pero cada uno tiene un cuarto de

kondor19780726 [428]

Answer:

Cuando María afirma que si unen sus dos cuartos de cartulina obtendrán el medio pliego que necesitan, esto es:

<u>Verdadero</u>.

Step-by-step explanation:

Para entender mejor el ejercicio vamos a utilizar números cada vez que se habla de cantidades de cartulina, por lo tanto, María y Juan tienen 1/4 de cartulina cada uno, es decir, 1/4 * 2, y necesitan 1/2 pliego para poder realizar su tarea, por lo tanto, con la afirmación de María sobre unir los dos cuartos de cartulina, en caso de que sea verdadero, ocurrirá que la suma de los dos cuartos dará el medio pliego, como se muestra a continuación:

Total de cartulina de María y Juan = $\frac{1}{4}+\frac{1}{4}$
Total de cartulina de María y Juan = $\frac{4+4}{16}$
Total de cartulina de María y Juan = $\frac{8}{16}$

Procedemos a simplificar el fraccionario obtenido, sacando mitad tanto en el numerador como en el denominador:

Total de cartulina de María y Juan = $\frac{4}{8}$
Total de cartulina de María y Juan = $\frac{2}{4}$
<u><em>Total de cartulina de María y Juan = </em></u> $\frac{1}{2}$ <u><em /></u>

Como puedes ver al final, <u>la cantidad de cartulina de ambos, al ser sumada, da como resultado el 1/2 (medio) pliego que necesitan para su tarea de sociales, por lo cual la afirmación de María es correcta</u>.

3 0

3 years ago