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3 years ago

Write all that apply plz

Mathematics

1 answer:

Taya2010 [7]3 years ago

6 0

the answers that apply are B, D, and F

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Sindi borrowed an amount of money from his father to open the Salon. The loan will be paid back by means of payments of R25 000

amm1812

The present value of the loan will be = R36,250

<h3>Calculation of the present value</h3>

The principal capital (P) = R25 000

Interest rate for the payment (R)= 7.5%

Time for the payment (T)= 6 years

Therefore simple interest = P×T×R/100

= 25,000×6×7.5/100

= 250×6×7.5

= R11,250

The present value of the loan will be;

= 25,000 + 11,250

= R36,250

Learn more about simple interest here:

brainly.com/question/20690803

#SPJ1

5 0

1 year ago

How do you solve this

love history [14]

Answer:

x=-2

Step-by-step explanation:

$\frac{1}{6{x}^{2} } = \frac{1}{2x} + \frac{7}{6 {x}^{2} } \\ \frac{7}{6 {x}^{2} } - \frac{1}{6{x}^{2} } + \frac{1}{2 {x} } = 0 \: \: \: \: \: ( - \frac{1}{6 {x}^{2} } \: throughout) \\ \frac{6}{6 {x}^{2} } + \frac{1}{2x} = 0 \: \: \: \: \: (simplify)\\ \frac{1}{ {x}^{2} } + \frac{1}{2x} = 0 \\ \frac{2 {x}^{2} }{ {x}^{2} } + \frac{2 {x}^{2} }{2x} = 0 \: \: \: \: \: ( \times 2 {x}^{2} \: throughout) \\ 2 + x = 0 \: \: \: \: \: (simplify)\\ x = - 2$

4 0

3 years ago

Alex makes 60% of the shots he takes in basketball. What is the probability that Alex

galina1969 [7]

Answer:60/100

Step-by-step explanation:

60/100 idk

7 0

2 years ago

Read 2 more answers

Guys I really need help! Please answer ASAP!

Korvikt [17]

Answer:

a)Pipeline Plunge (-1,2)

b)Wonder Wheel (2,-4)

c)Big Coaster (-3,1)

d)(-1,-2)

6 0

2 years ago

19) Given that f(x)x² - 8x+ 15x² - 25find the horizontal and vertical asymptotes using the limits of the function.A) No Vertical

Tems11 [23]

EXPLANATION

Since we have the function:

$f(x)=\frac{x^2-8x+15}{x^2}$

Vertical asymptotes:

$For\:rational\:functions,\:the\:vertical\:asymptotes\:are\:the\:undefined\:points,\:also\:known\:as\:the\:zeros\:of\:the\:denominator,\:of\:the\:simplified\:function.$

Taking the denominator and comparing to zero:

$x+5=0$

The following points are undefined:

$x=-5$

Therefore, the vertical asymptote is at x=-5

Horizontal asymptotes:

$\mathrm{If\:denominator's\:degree\:>\:numerator's\:degree,\:the\:horizontal\:asymptote\:is\:the\:x-axis:}\:y=0.$ $If\:numerator's\:degree\:=\:1\:+\:denominator's\:degree,\:the\:asymptote\:is\:a\:slant\:asymptote\:of\:the\:form:\:y=mx+b.$ $If\:the\:degrees\:are\:equal,\:the\:asymptote\:is:\:y=\frac{numerator's\:leading\:coefficient}{denominator's\:leading\:coefficient}$ $\mathrm{If\:numerator's\:degree\:>\:1\:+\:denominator's\:degree,\:there\:is\:no\:horizontal\:asymptote.}$ $\mathrm{The\:degree\:of\:the\:numerator}=1.\:\mathrm{The\:degree\:of\:the\:denominator}=1$ $\mathrm{The\:degrees\:are\:equal,\:the\:asymptote\:is:}\:y=\frac{\mathrm{numerator's\:leading\:coefficient}}{\mathrm{denominator's\:leading\:coefficient}}$ $\mathrm{Numerator's\:leading\:coefficient}=1,\:\mathrm{Denominator's\:leading\:coefficient}=1$ $y=\frac{1}{1}$ $\mathrm{The\:horizontal\:asymptote\:is:}$ $y=1$

In conclusion:

$\mathrm{Vertical}\text{ asymptotes}:\:x=-5,\:\mathrm{Horizontal}\text{ asymptotes}:\:y=1$

4 0

1 year ago

Write all that apply plz​

Write all that apply plz