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3 years ago

139,852 in word form.

Mathematics

2 answers:

LuckyWell [14K]3 years ago

5 0

One hundred and thirty nine thousand , eight hundred and fifty two.

Well at least how i would work it.

RideAnS [48]3 years ago

4 0

One hundred thirty-nine thousand, eight hundred fifty-two

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Shane and Karen want to measure the length of a soccer field. Should they use centimeters or meters to measure it? Explain.

Ber [7]

Shane and Karen want to measure the length of a soccer field. Length can be measured in different units such as cm, m ,km , yards etc. The question is asking us to select between two units cm or meters which will be more appropriate to measure the field.

To measure the field a larger unit is required. Meter is a bigger unit than centimeter.Centimeter is not the correct unit to measure the length of soccer field.

Shane and Karen should use meters to measure the soccer field.

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3 years ago

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How can I find the area and perimeter of the circle? pls help

strojnjashka [21]

The perimeter of the circle is also known as the circumference that said figure out what the diameter is and multiply that by pi (3.14)

8 0

3 years ago

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Find the percent of increase or decrease. Round to the nearest tenth of a percent where necessary.

Umnica [9.8K]

Answer:

Step-by-step explanation:

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8 0

3 years ago

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Yo please help

Alex Ar [27]

Answer:

Options 1, 3 and 4 are true

Step-by-step explanation:

The legs EF and DF of the right triangle DEF have lengths of 24 units and 7 units, respectively. By the Pythagorean theorem,

$DE^2=EF^2+DF^2\\ \\DE^2=24^2+7^2\\ \\DE^2=576+49\\ \\DE^2=625\\ \\DE=25\ units$

Find trigonometric functions:

$\sin \angle D=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{EF}{DE}=\dfrac{24}{25}$

$\cos \angle E=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}=\dfrac{EF}{DE}=\dfrac{24}{25}$

$\tan \angle D=\dfrac{\text{Opposite leg}}{\text{Adjacent leg}}=\dfrac{EF}{DF}=\dfrac{24}{7}$

$\sin \angle E=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{DF}{DE}=\dfrac{7}{25}$

Thus, options 1, 3 and 4 are true

5 0

3 years ago

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You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co

alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

$P=2x+2y$

On the other hand, since the available money to buy fence is D dollars,

$\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}$

Furthermore, the area of the enclosed land is given by

$A=xy$

Solving the second equation for x,

$\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}$

Substituting into the equation for the area,

$\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}$

To find the maximum possible area, solve A'(y)=0, as shown below

$\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}$

Therefore, the corresponding value of x is

$\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}$ <h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2> $\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}$ <h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

7 0

1 year ago