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ale4655 [162]
3 years ago
9

139,852 in word form.

Mathematics
2 answers:
LuckyWell [14K]3 years ago
5 0
One hundred and thirty nine thousand , eight hundred and fifty two.

Well at least how i would work it.
RideAnS [48]3 years ago
4 0
One hundred thirty-nine thousand, eight hundred fifty-two
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Georgia [21]
Lena’s guest house is 8 m long
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3 years ago
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How can you place value and period names to read and write 12,324,904 in word form?
FrozenT [24]
It is written/spoken like so:

"Twelve million three hundred and twenty four thousand nine hundred and four"

6 0
3 years ago
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Rectangular classroom seats 72 students. If the seats were rearragned with 3 more seats rows in each row, the classroom would ha
Gre4nikov [31]
<span>Let the original number of seats in a row be x;
</span>Let the number rows be y;

( x + 3) * (y - 2 )= 72 and x * y = 72 => 72 + 3 * y - 2 * x = 72 => 3 * y = 2 * x;
=> x is divisible by 3;

1. x = 3 => y = 72 / 3 => y = 24;
2. x = 6 => y = 72 / 6 => y = 12;
3. x = 9 => y = 72 / 9 => y = 8;
4. x = 12 => y = 72 / 12 =. y = 6;
5. x = 24 =. y = 72 / 24 => y = 3;
6. x = 36 => y = 72 / 36 => y = 2;
7. x = 72 => y = 72 / 72 => y = 1;

My analysis tell me that the right answer is 9 seats in a row and 8 rows;
The original number in each row is 9.
6 0
3 years ago
What is the lcd of (3x)/(x + 3), 3/(x ^ 2 - 9)
Rudik [331]

Answer:

Simplify the denominator.

Tap for more steps...

x

(

x

+

3

)

(

x

−

3

)

⋅

3

x

x

2

−

5

x

+

6

Factor

x

2

−

5

x

+

6

using the AC method.

Tap for more steps...

x

(

x

+

3

)

(

x

−

3

)

⋅

3

x

(

x

−

3

)

(

x

−

2

)

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

(

x

+

3

)

(

x

−

3

)

,

(

x

−

3

)

(

x

−

2

)

The LCM is the smallest positive number that all of the numbers divide into evenly.

1. List the prime factors of each number.

2. Multiply each factor the greatest number of times it occurs in either number.

The number

1

is not a prime number because it only has one positive factor, which is itself.

Not prime

The LCM of

1

,

1

is the result of multiplying all prime factors the greatest number of times they occur in either number.

1

The factor for

x

+

3

is

x

+

3

itself.

(

x

+

3

)

=

x

+

3

(

x

+

3

)

occurs

1

time.

The factor for

x

−

3

is

x

−

3

itself.

(

x

−

3

)

=

x

−

3

(

x

−

3

)

occurs

1

time.

The factor for

x

−

2

is

x

−

2

itself.

(

x

−

2

)

=

x

−

2

(

x

−

2

)

occurs

1

time.

The LCM of

x

+

3

,

x

−

3

,

x

−

3

,

x

−

2

is the result of multiplying all factors the greatest number of times they occur in either term.

(

x

+

3

)

(

x

−

3

)

(

x

−

2

)

Step-by-step explanation:

there does that help

6 0
3 years ago
Help me on this question please​
Luba_88 [7]
Sorry hun I’ve never learned that
5 0
3 years ago
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