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mamaluj [8]
3 years ago
7

Hte area of a rectangle trampoline is 112 ft^2. the length of the trampoline is 6ft greater than the width of the trampoline, th

is situation can be represented by the equation w^2+6w-112=0
what is the lengeth of the trampoline in feet?
7
16
8
14
Mathematics
2 answers:
djverab [1.8K]3 years ago
7 0

Answer:

C. 8 ft.

Step-by-step explanation:

start by identifying your a (1), b (6), and c(-112). you plug them into the quadratic formula or by using this calculator https://www.calculatorsoup.com/calculators/algebra/quadratic-formula-calculator.php. the two solutions will be x = 8 and x = -14, but of course the reasonable answer is 8 and none of the choices are -14.

Brrunno [24]3 years ago
5 0

Answer:

Step-by-step explanation:

alright, lets get started.

suppose the width is w.

the length is 6 feet greater than the width, so

length will be = w+6

area of the trampoline = length*width

area=(w+6)*w = w^2 +6w

as per given, area is 112, so

w^2+6w=112

subtracting 112 in both sides

w^2+6w-112=0

factoring

(w-8)(w+14)=0

So, it will give two values of w

w=8 and w = -14

The width can't be negative, so

width = 8 feet.    :   answer

Hope it will help :)

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