Question

Hte area of a rectangle trampoline is 112 ft^2. the length of the trampoline is 6ft greater than the width of the trampoline, this situation can be represented by the equation w^2+6w-112=0
what is the lengeth of the trampoline in feet?
7
16
8
14

Answer 1

Answer:

C. 8 ft.

Step-by-step explanation:

start by identifying your a (1), b (6), and c(-112). you plug them into the quadratic formula or by using this calculator https://www.calculatorsoup.com/calculators/algebra/quadratic-formula-calculator.php. the two solutions will be x = 8 and x = -14, but of course the reasonable answer is 8 and none of the choices are -14.

Answer 2

Answer:

Step-by-step explanation:

alright, lets get started.

suppose the width is w.

the length is 6 feet greater than the width, so

length will be = w+6

area of the trampoline = length*width

$area=(w+6)*w = w^2 +6w$

as per given, area is 112, so

$w^2+6w=112$

subtracting 112 in both sides

$w^2+6w-112=0$

factoring

$(w-8)(w+14)=0$

So, it will give two values of w

w=8 and w = -14

The width can't be negative, so

width = 8 feet.    :   answer

Hope it will help :)