Water is contained in a piston-cylinder assembly undergoes four processes separately, all started from an initial state where th
e pressure is p1, the temperature is T1, and the specific volume is v1:
Process 1→2: Constant temperature (isothermal) to p2 = 2p1; Process 1→3: Constant specific volume to p3 = 2p1;
Process 1→4: Constant pressure (isobaric) to v4 = 2v1; Process 1→5: Constant temperature (isothermal) to v5 = 2v1.
Draw a p-v diagram and a T-v diagram for the water including the saturated liquid line and the saturated vapor line (dome).
The initial state (state 1) is at the saturated vapor state, note down state 2, 3, 4 and state 5 on both diagrams, and draw all processes (Process 1→2, 1→3, 1→4 and 1→5)
Process 1→2: Constant temperature (isothermal) to p2 = 2p1; Process 1→3: Constant specific volume to p3 = 2p1;
Process 1→4: Constant pressure (isobaric) to v4 = 2v1; Process 1→5: Constant temperature (isothermal) to v5 = 2v1.
Draw a p-v diagram and a T-v diagram for the water including the saturated liquid line and the saturated vapor line (dome).
The initial state (state 1) is at the saturated vapor state, note down state 2, 3, 4 and state 5 on both diagrams, and draw all processes (Process 1→2, 1→3, 1→4 and 1→5)
1 answer:
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Answer:
Explanation:
= Area of section 1 =
= Velocity of water at section 1 = 100 ft/min
= Specific volume at section 1 =
= Density of fluid =
= Area of section 2 =
Mass flow rate is given by
The mass flow rate through the pipe is
As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1
The speed at section 2 is .
Maximum shear stress in the pole is 0.
<u>Explanation:</u>
Given-
Outer diameter = 127 mm
Outer radius, = 127/2 = 63.5 mm
Inner diameter = 115 mm
Inner radius, = 115/2 = 57.5 mm
Force, q = 0
Maximum shear stress, τmax = ?
τmax
If force, q is 0 then τmax is also equal to 0.
Therefore, maximum shear stress in the pole is 0.