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Nikitich [7]
3 years ago
12

Water is contained in a piston-cylinder assembly undergoes four processes separately, all started from an initial state where th

e pressure is p1, the temperature is T1, and the specific volume is v1:
Process 1→2: Constant temperature (isothermal) to p2 = 2p1; Process 1→3: Constant specific volume to p3 = 2p1;

Process 1→4: Constant pressure (isobaric) to v4 = 2v1; Process 1→5: Constant temperature (isothermal) to v5 = 2v1.

Draw a p-v diagram and a T-v diagram for the water including the saturated liquid line and the saturated vapor line (dome).

The initial state (state 1) is at the saturated vapor state, note down state 2, 3, 4 and state 5 on both diagrams, and draw all processes (Process 1→2, 1→3, 1→4 and 1→5)

Engineering
1 answer:
Andrews [41]3 years ago
3 0

Answer:

see pictures

Explanation:

In the pictures you can see the different processes.

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Using an "AND" and an "OR", list all information (Equipment Number, Equipment Type, Seat Capacity, Fuel Capacity, and Miles per
Tomtit [17]

Answer:

Explanation :

The given  information to be listed can are Equipment Number, Equipment Type, Seat Capacity, Fuel Capacity, and Miles per Gallon.

Check the attached document for the solution.

5 0
3 years ago
A car engine with a thermal efficiency of 33% drives the air-conditioner unit (a refrigerator) besides powering the car and othe
fgiga [73]

Answer:

The rate of fuel required to drive the air conditioner Q_h = 6.061 kW

The flow rate of the cold air is  \r m = 0.30765 kg/s

Explanation:

From this question we are told that

    The efficiency is \eta = 33% = 0.33

   Temperature for the hot day is  T_h = 35^oC = 308 K \  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (35+273)

        Temperature after cooling is  T_c = 5^oC = 278K

      The input power is  P_{in} = 2kW

The rate of fuel required to drive the air conditioner can be mathematically represented as

              Q_h = \frac{P_{in}}{\eta}

                    = \frac{2}{0.33} = 6.061 kW

From the question the air condition is assumed to be half as a Carnot refrigeration unit

 This can be Mathematically interpreted in terms of COP(coefficient of performance) as

             \beta_{air} = 0.5 \beta

where \beta  denotes COP and is mathematically represented as

                     \beta = \frac{Q_c}{P_{in}}

= >              Q_c = \beta P_{in}

Where Q_c is the rate of flue being burned for cold air to flow

Now if  the COP of a Carnot refrigerator is having this value

                \beta_{Carnot } = \frac{T_c}{T_h - T_c}

                            = \frac{278}{308-278}

                            \beta_{Carnot} = 9.267\\

Then

     \beta_{air} = 0.5 * 9.2667

            = 4.6333

Now substituting the value of \beta to solve for Q_c

                             Q_c = \beta P_{in}

                                  = 4.6333 *2

                                  9.2667kW

The equation for the rate of fuel being burned for the cold air to flow

                       Q_c = \r mc_p \Delta T

Making the flow rate of the cold air

                       \r m = \frac{Q_c}{c_p \Delta T}

                            = \frac{9.2667}{1.004}* (308 - 278)

                            = 0.30765 kg/s

                         

                             

4 0
3 years ago
If the contact surface between the 20-kg block and the ground is smooth, determine the power of force F when t = 4 s. Initially,
grigory [225]

Answer:

The power of force F is 115.2 W

Explanation:

Use following formula

Power  = F x V

F_{H} = F cos0

F_{H} = (30) x 4/5

F_{H} = 24N

Now Calculate V using following formula

V = V_{0} + at

V_{0} = 0

a = F_{H} / m

a = 24N / 20 kg

a = 1.2m / S^{2}

no place value in the formula of V

V = 0 + (1.2)(4)

V = 4.8 m/s

So,

Power = F_{H} x V

Power = 24 x 4.8

Power = 115.2 W

3 0
3 years ago
A displacement transducer has the following specifications: Linearity error ± 0.25% reading Drift ± 0.05%/○C reading Sensitivity
White raven [17]

Answer:

The Estimated uncertainty in a nominal displacement of 2 cm at the design stage is plus or minus 0.0124cm

Explanation:

uncertainty in a nominal displacement

= (u^2 + v^2)^(1/2)

assume from specifications that k = 5v/5cm

                                                         = 1v/cm

u^2 = (0.0025*2)^(2) + (0.005*10*2)^2 + (0.0025*2)^2

      = 0.01225v

v = 2v * 0.001

  = 0.002v

uncertainty in a nominal displacement

= (u^2 + v^2)^(1/2)

= ((0.01225)^2 + (0.002)^2)^(1/2)

= 0.0124 cm

Therefore, The Estimated uncertainty in a nominal displacement of 2 cm at the design stage is plus or minus 0.0124cm

8 0
3 years ago
A Si sample contains 1016 cm-3 In acceptor atoms and a certain number of shallow donors, the In acceptor level is 0.16 eV above
creativ13 [48]

Answer:

6.5 × 10¹⁵/ cm³

Explanation:

Thinking process:

The relation N_{o} = N_{i} * \frac{E_{f}-E_{i}  }{KT}

With the expression Ef - Ei = 0.36 × 1.6 × 10⁻¹⁹

and ni = 1.5 × 10¹⁰

Temperature, T = 300 K

K = 1.38 × 10⁻²³

This generates N₀ = 1.654 × 10¹⁶ per cube

Now, there are 10¹⁶ per cubic centimeter

Hence, N_{d}  = 1.65*10^{16}  - 10^{16} \\           = 6.5 * 10^{15} per cm cube

5 0
3 years ago
Read 2 more answers
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