Answer:
Explanation:
From the information given:
a.
Using the equipartition theorem, the average energy of a molecule dor each degree of freedom is:


For s degree of freedom

However, the molar specific heat 
Therefore, in terms of R and s;


b.
Given that:
Cv=70.6Jmol⋅K and R=8.314Jmol⋅K
Then; using the formula



s = 16.983
s
17
Answer:
Absolute pressure , P(abs)= 433.31 KPa
Explanation:
Given that
Gauge pressure P(gauge)= 50 psi
We know that barometer reads atmospheric pressure
Atmospheric pressure P(atm) = 29.1 inches of Hg
We know that
1 psi = 6.89 KPa
So 50 psi = 6.89 x 50 KPa
P(gauge)= 50 psi =344.72 KPa
We know that
1 inch = 0.0254 m
29.1 inches = 0.739 m
Atmospheric pressure P(atm) = 0.739 m of Hg
We know that density of Hg =
P = ρ g h
P(atm) = 13.6 x 1000 x 9.81 x 0.739 Pa
P(atm) = 13.6 x 9.81 x 0.739 KPa
P(atm) =98.54 KPa
Now
Absolute pressure = Gauge pressure + Atmospheric pressure
P(abs)=P(gauge) + P(atm)
P(abs)= 344.72 KPa + 98.54 KPa
P(abs)= 433.31 KPa
Answer:
import java.io.*;
import java.util.Scanner;
public class CountWordsInFile {
public static void main(String[] args) throws IOException {
Scanner keyboard = new Scanner(System.in);
System.out.print("Enter file name: ");
String fileName = keyboard.next();
File file = new File(fileName);
try {
Scanner scan = new Scanner(file);
int count = 0;
while(scan.hasNext()) {
scan.next();
count += 1;
}
scan.close();
System.out.println("Number of words: "+count);
} catch (FileNotFoundException e) {
System.out.println("File " + file.getName() + " not present ");
System.exit(0);
}
}
}
Answer:
Yield strength, tensile strength decreases with increasing temperature and modulus of elasticity decreases with increasing in temperature.
Explanation:
The modulus of elasticity of a material is theoretically a function of the shape of curve plotted between the potential energy stored in the material as it is loaded versus the inter atomic distance in the material. The temperature distrots the molecular structure of the metal and hence it has an effect on the modulus of elasticity of a material.
Mathematically we can write,
![E(t)=E_o[1-a\frac{T}{T_m}]](https://tex.z-dn.net/?f=E%28t%29%3DE_o%5B1-a%5Cfrac%7BT%7D%7BT_m%7D%5D)
where,
E(t) is the modulus of elasticity at any temperature 'T'
is the modulus of elasticity at absolute zero.
is the mean melting point of the material
Hence we can see that with increasing temperature modulus of elasticity decreases.
In the case of yield strength and the tensile strength as we know that heating causes softening of a material thus we can physically conclude that in general the strength of the material decreases at elevated temperatures.
Answer:
Bimetallic strip is a strip consisting of two metals of different coefficients of expansion welded together so that it buckles on heating : used in thermostats.