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4 years ago

What two numbers multiply to -27 and add to 1

Mathematics

1 answer:

Westkost [7]4 years ago

6 0

Answer:

3 x 9, 1 x 27, 9 x 3

Step-by-step explanation:

you have to multiple 3 x 9 to get to 27. you have to multiple 1 x 27 to get 27. you have to multiple 9 x 3 to get 27.

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Janette went to Tire Mart and paid $122.57 per tire for 4 tires and a flat rate fee for installation for a total of $555.28 befo

kodGreya [7K]

122.57 ×4=490.28 Total was 555.28 which would be a difference of 65.00 136.71 ×4=546.84 Total was 585.34 which would be a difference of 38.50 Subtract the two differences which is $26.50

8 0

3 years ago

At a play, 117 tickets were sold. Adult tickets cost 2.50 and children’s tickets cost 1.00. In all 243$ was taken in. How many o

Agata [3.3K]

Answer:

Adult tickets = 84

Children tickets = 33

Step-by-step explanation:

At a play 117 tickets were sold.

Adult's tickets (a) cost $2.50 each and,

Children's (c) tickets cost $1.00 each

Money collected = $243

This is the simultaneous equation formed:

a + c = 117 ... (i)

2.5a + c = 243 ... (ii)

Subtracting (ii) - (i) we get;

1.5a = 126

a = 126 ÷ 1.5 = 84

So there were 84 adult's tickets sold and 117 - 84 = 33 children's tickets sold.

7 0

3 years ago

Sum of two numbers is 58 and the smaller number is 20 less than the larger number

Dmitrij [34]

Answer:

X=38 ANS. FOR THE LARGER NUMBER.

Y=20 ANS. FOR THE SMALLER NUMBER.

Step-by-step explanation:

38+Y=58

Y=58-38

38-20=18

18=18

3 0

3 years ago

The body of a soda can (in between the lid and the bottom) is a cylinder. If the body is about 4.5 inches tall with a diameter o

Ad libitum [116K]

Answer: V=7.605π

Step-by-step explanation:

The cylinder formula is V=πr^2h

Substitute the values.

V=π(1.3)^2(4.5)

V=π(1.69)(4.5)

V=7.605π

Hope this helps!

7 0

3 years ago

Differentiate Vx(x + 2) with respect to x.

Travka [436]

Answer:

$y'= \frac{3x+2}{2\sqrt{x} }$

General Formulas and Concepts:

Calculus

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

$y=\sqrt{x} (x+2)$

Step 2: Rewrite

$y=x^{\frac{1}{2} } (x+2)$

Step 3: Differentiate

Product Rule [Basic Power/Chain Rule]: $y'= \frac{1}{2} x^{\frac{1}{2} -1}(x+2)+x^{\frac{1}{2} }(1)$
Simplify: $y'= \frac{1}{2} x^{\frac{-1}{2}}(x+2)+x^{\frac{1}{2}}$
Rewrite: $y'= \frac{x+2}{2\sqrt{x} } + \sqrt{x}$
Add: $y'= \frac{3x+2}{2\sqrt{x} }$

7 0

3 years ago