The volume is 12 mL (0.012 L)
Before the aluminum was added, the water reached 132mL. After it was added, it reached 144. That means the Aluminum takes up (144-132)= 12mL of space.
The density = mass/volume. If the aluminum bar has a mass of 78g and volume of 0.012L, 78/0.012=6,500 g/L
Answer:
0.0002949 moles
Explanation:
Concentration = 2.02×10−2 M
Volume = 14.6 mL = 0.0146 L (Upon converting to litres)
Number of moles = ?
These variables are related by the fllowing equation;
Concentration = Number of moles / Volume
Number of moles = Concentration * Volume
Number of moles = 2.02×10−2 * 0.0146 = 0.0002949 moles
Answer:
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