In a receptacle we have 29 g of hydrochloric acid that react with an excess of ammonia according the following equation:

What are all of the elements that end with F electrons

jonny [76]

The elements whose electron configurations end with f electrons are in the Lanthanide and Actinide series: those long series at the bottom of the Periodic Table (see image).

The atoms are adding electrons into f orbitals, but the f electrons are not always the last electrons in the electron configuration.

For example, the electron configuration of Eu is [Xe]6s²4f⁷, but that of Gd

is [Xe] 6s²4f⁷5d.

I have blocked off in <em>red</em> all the <em>exceptions</em> like Gd.

5 0

3 years ago

Suppose you were to read about a scientific statement based on data from hundreds of years of research and observation that appl

Dominik [7]

Answer:

theory

Explanation:

A theory has been tested and proven several times and oftentimes has a large amount of information, research, and evidence standing behind it.

Hope this helps! :)

5 0

3 years ago

Typical frequencies for several types of electromagnetic radiation are given below. Calculate the energy of each type of radiati

marusya05 [52]

Explanation:

The energy of electromagnetic radiation is given by :

$E=h\nu$

Where, h is the Planck's constant

(a) A gamma ray, $\nu = 1.64\times 10^{20}\ Hz$

Energy,

$E=6.63\times 10^{-34}\times 1.64\times 10^{20}\\E=1.08\times 10^{-13}\ J$

(b) A microwave, $\nu = 4.95\times 10^{10}\ Hz$

Energy,

$E=6.63\times 10^{-34}\times 4.95\times 10^{10}\\E=3.28\times 10^{-23}\ J$

(c) A AM radio wave, $\nu = 2\times 10^{6}\ Hz$

Energy,

$E=6.63\times 10^{-34}\times 2\times 10^{6}\\E=1.32\times 10^{-27}\ J$

Therefore, this is the required solution.

4 0

3 years ago

Question ( please help me )

levacccp [35]

Answer:

1. F, H, E

2. A, D, I

3. G

4. E, B, H

5. C

Explanation:

4 0

2 years ago

Sodium-25 was to be used in an experiment, but it took 3.0 minutes to get the sodium from the reactor to the laboratory. If 8.0

Ksenya-84 [330]

Sodium-25 after 3 minutes : 1.0625 mg

<h3>Further explanation</h3>

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}$

T = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

<h3 />

No=8 mg

t1/2=60 s

T=3 min=180 s

$\tt Nt=No\dfrac{1}{2}^{T/t1/2}\\\\Nt=8.5\dfrac{1}{2}^{180/60}\\\\Nt=8.5(\dfrac{1}{2})^3\\\\Nt=1.0625~mg$

5 0

3 years ago