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Julli [10]
2 years ago
6

In a receptacle we have 29 g of hydrochloric acid that react with an excess of ammonia according the following equation:

Chemistry
1 answer:
NemiM [27]2 years ago
5 0

Answer:

2969429th Ave

Explanation:

i dont know

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saul85 [17]
Rarely they can't with just sight. Certain tests or experiments should take place
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3 years ago
Calcium must lose two electrons to get a full outer shell. what is the name of the group to which calcium belongs
11111nata11111 [884]
The answer to this question would be: alkaline earth metal

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How many moles are present in 25.0 grams of potassium permanganate, KMnO,? ​
poizon [28]

Answer: 0.158

Explanation:

7 0
3 years ago
Th e molar absorption coeffi cient of a substance dissolved in water is known to be 855 dm3 mol−1 cm−1 at 270 nm. To determine t
Olegator [25]

Answer : The percentage reduction in intensity is 79.80 %

Explanation :

Using Beer-Lambert's law :

A=\epsilon \times C\times l

A=\log \frac{I_o}{I}

\log \frac{I_o}{I}=\epsilon \times C\times l

where,

A = absorbance of solution

C = concentration of solution = 3.25mmol.dm^{3-}=3.25\times 10^{-3}mol.dm^{-3}

l = path length = 2.5 mm = 0.25 cm

I_o = incident light

I = transmitted light

\epsilon = molar absorptivity coefficient = 855dm^3mol^{-1}cm^{-1}

Now put all the given values in the above formula, we get:

\log \frac{I_o}{I}=(855dm^3mol^{-1}cm^{-1})\times (3.25\times 10^{-3}mol.dm^{-3})\times (0.25cm)

\log \frac{I_o}{I}=0.6947

\frac{I_o}{I}=10^{0.6947}=4.951

If we consider I_o = 100

then, I=\frac{100}{4.951}=20.198

Here 'I' intensity of transmitted light = 20.198

Thus, the intensity of absorbed light I_A = 100 - 20.198 = 79.80

Now we have to calculate the percentage reduction in intensity.

\% \text{reduction in intensity}=\frac{I_A}{I_o}\times 100

\% \text{reduction in intensity}=\frac{79.80}{100}\times 100=79.80\%

Therefore, the percentage reduction in intensity is 79.80 %

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3 years ago
For the following questions protons are blue and neutrons are red
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I can’t see the picture where’s it at
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