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3 years ago

How does nuclear pull and shielding electrons affects ionization energy in the same period?

Chemistry

1 answer:

Romashka-Z-Leto [24]3 years ago

8 0

Answer:

Explanation:

Going across a period, the effective nuclear charge increase (b/c you are at the same energy level "n" and you are adding more protons) so the electrons are harder to remove and the ionization energy increases. Shielding does not really affect the nuclear pull across the period b/c you are not going farther away from nucleus as you move across a period (you move farther away when you move down a group) you are staying in the same period just adding more protons which increases the pull on electrons and making it harder to remove electrons thus ionization energy increases.

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Use the ideal gas law to calculate the concentrations of nitrogen and oxygen present in air at a pressure of 1.0 atm and a tempe

notka56 [123]

Answer:

[N₂] = 0.032 M

[O₂] = 0.0086 M

Explanation:

Ideal Gas Law → P . V = n . R . T

We assume that the mixture of air occupies a volume of 1 L

78% N₂ → Mole fraction of N₂ = 0.78

21% O₂ → Mole fraction of O₂ = 0.21

1% another gases → Mole fraction of another gases = 0.01

In a mixture, the total pressure of the system refers to total moles of the mixture

1 atm . 1L = n . 0.082L.atm/mol.K . 298K

n = 1 L.atm / 0.082L.atm/mol.K . 298K → 0.0409 moles

We apply the mole fraction to determine the moles

N₂ moles / Total moles = 0.78 → 0.78 . 0.0409 mol = 0.032 moles N₂

O₂ moles / Total moles = 0.21 → 0.21 . 0.0409 mol = 0.0086 moles O₂

4 0

3 years ago

The functional structure of a protein is its _________________ structure, which is ultimately determined by the ________________

Dmitriy789 [7]

Answer:

Explanation:

The tertiary structure of proteins is related to the interactions between the amino acids of the primary structure. Thus, these interactions give it a specific three-dimensional configuration which is very sensitive to functionality.

For example, allosteric inhibitions are related to this concept. When the inhibitor changes the tertiary structure of the protein it loses all activity and for the catalysis of the reaction.

Thus, the primary structure (which is related to the specific sequence of amino acids) will determine the tertiary structure since the chain folds will be a consequence of intra-amino acid interactions.

8 0

3 years ago

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The half-life of nitrogen-13 is 10.0 minutes. if you begin with 53.3 mg of this isotope, what mass remains after 25.9 minutes ha

zimovet [89]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 53.3 mg

m (final mass after time T) = ? (in mg)

x (number of periods elapsed) = ?

P (Half-life) = 10.0 minutes

T (Elapsed time for sample reduction) = 25.9 minutes

Let's find the number of periods elapsed (x), let us see:

$T = x*P$

$25.9 = x*10.0$

$25.9 = 10.0\:x$

$10.0\:x = 25.9$

$x = \dfrac{25.9}{10.0}$

$\boxed{x = 2.59}$

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

$m = \dfrac{m_o}{2^x}$

$m = \dfrac{53.3}{2^{2.59}}$

$m \approx \dfrac{53.3}{6.021}$

$\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

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2 years ago

Explain why a luminous flame of a Bunsen burner produces bright yellow light

telo118 [61]

Answer:

because of the small soot particles

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2 years ago

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According to the Kinetic Energy Theory, the more energy a particle has, the _______ it moves.

MissTica

B and temp is related to kinetic energy by how they both effect the speed of the particles. If the temp is hot the particles speed up and if cold the particles slow down

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3 years ago

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