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4 years ago

What are the processes for the 3 types of weathering

1 answer:

7 0

The processes for the 3 types of weathering are,
biological: rocks worn down by plants
physical: water freezing and thawing in cracks of rocks
chemical: Acid rain
Hope this helped!!

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A patient needs to take 625 mg of ibuprofen twice daily. The pills in the bottle are each 250. mg. How many pills does the patie

Vladimir [108]

The answer is 2 and 1/2 pills
250+250=500 which is two pills then half of 250 is 125 which is half a pill

5 0

3 years ago

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Compound x is converted to elements a and b. compound x has undergone a _____ reaction.

maw [93]

Decomposition reaction

3 0

3 years ago

Question 6 of 30

Brilliant_brown [7]

Answer:

its letter c

Explanation:

I hope this help

6 0

3 years ago

A tetrahedron is like a pyramid, but with a triangular base. How might atoms bond to form this shape?

Nata [24]

Tetrahedron generally known as triangular pyramid consists of 4 triangular faces, 6 edges and 4 vertices. The base of the tetrahedron is a triangle. All the vertices have the same atom that is bonded to the central metal atom which lies in the centre of the tetrahedron. We take $[SiO_4]^4^-$ as an example to see how the atoms actually bond in tetrahedron. It is quite visible from the image that 4 O-atoms lies on all the 4 vertices and 1 Si-atom lie in the centre.

7 0

4 years ago

Suppose two 200.0-L tanks are to be filled separately with the gases helium and hydrogen. What mass of each gas is needed to pro

Aneli [31]

Answer:

Mass of helium = 4426.9524 g

Mass of hydrogen gas = 2213.4762 g

Explanation:

Pressure = 135 atm

Temperature = 24 °C

Volume = 200 L

Number of moles = ?

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (24 + 273.15) K = 297.15 K

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

135 atm × 200 L = n × 0.0821 L.atm/K.mol × 297.15 K

⇒n = 1106.7381 moles

For helium gas:

Molar mass = 4 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$1106.7381= \frac{Mass}{4}$

$Mass= 4426.9524\ g$

For hydrogen gas:

Molar mass = 2 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$1106.7381= \frac{Mass}{2}$

$Mass= 2213.4762\ g$

4 0

4 years ago