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ki77a [65]
3 years ago
5

5.

Physics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Answer: black

Explanation: When green light is shone on a red object, it absorbs all of the green light and not reflecting anything. Hence, it appears black.

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How do different factors affect solubility? Check all of the boxes that apply.
Karo-lina-s [1.5K]

Answer:

Explanation:

Solubility is affected by current concentration, mechanical disturbance, temperature and pressure. So the answers are:

- Increasing temperature decreases the solubility of gases.

- Stirring increases the solubility of solids.

- Increasing pressure increases the solubility of gases.

- Decreasing the amount of solvent decreases the solubility of solids, liquids, and gases.

4 0
2 years ago
Read 2 more answers
A projectile is fired with an initial speed of 51.2 m/s at an angle of 44.5 degrees above the horizontal on a long flat firing r
irinina [24]
Use the projectile motion equations

H = v^2 x sin^2(θ) ÷ 2g

t = 2 x v x sinθ ÷ g

R = v^2 x sin2θ ÷ g
3 0
3 years ago
The scientist who used a prism to study light was _____.
DanielleElmas [232]
The scientist who used a prism to study light was Isaac Newton
3 0
3 years ago
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Sam is observing the velocity of a car at different times. After two hours, the velocity of the car is 54 km/h. After four hours
MariettaO [177]
With that information you can only suppose a uniformly accelerated motion.  This is, acceleration is constant.

Then, acceleration = change in velocity / change in time = (58 -54)km/h / 2 h = 4km/h / 2 h = 2 km/h^2

Then the equation for velocity, V is

V = Vo + a*t = Vo + 2 (km/h^2)  * t = Vo +  2t

Vo is the initial velocity, which you can find using V = 54km/h and t = -2

Vo = V after 2 hours - a*(2hours) = 54km/h - 2(km/h^2)*2h = 54km/k - 4km/h = 50km/h

Then, the equation is: V = 50 km/h + 2t

Valid for constant acceleration. 
5 0
2 years ago
A 0.473 kg ice puck, moving east with a speed of 2.76 m/s, has a head-on collision with a 0.819 kg puck initially at rest. Assum
Gekata [30.6K]

Answer:

The final speed of puck 1 is 0.739 m/s towards west  and puck 2 is 2.02 m/s towards east .

Explanation:

Let us consider east as positive direction and west as negative direction .

Given

mass of puck 1 , m_1= 0.473 kg

mass of puck 2 , m_2= 0.819 kg

initial speed of puck 1 , u_1=2.76\frac{m}{s}

initial speed of puck 2 , u_2=0.00\frac{m}{s}

Final speed of puck 1 and puck 2 be v_1\, and\, v_2  respectively

Apply conservation of linear momentum

m_1u_1+m_2u_2=m_1v_1+m_2v_2

=>0.473\times 2.76+0.0=0.473\times v_1+0.819\times v_2

=>1.594=0.5775\times v_1+ v_2 -----(A)

Since collision is perfectly elastic , coefficient restitution e=1

u_2-u_1=v_1-v_2

=>0-2.76=v_1-v_2 ------(B)

From equation (A) and (B)

v_1=-0.739\frac{m}{s}

and v_2=2.02\frac{m}{s}

Thus the final speed of puck 1 is 0.739 m/s towards west  and puck 2 is 2.02 m/s towards east .

       

3 0
3 years ago
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