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Maurinko [17]
3 years ago
14

A dock worker pulls two boxes connected by a rope on a horizontal floor, as shown in the figure . All the ropes are horizontal,

and there is some friction with the floor.Make a free-body diagram of the box B.

Physics
2 answers:
puteri [66]3 years ago
7 0

Answer:

The worker pulls the boxes. The force (F) on box B acts towards right direction. The weigh (mg) of the box acts in the downward direction where as reaction force -Normal force (N) acts in the upward direction.

The contact surface between box  and ground is not smooth and hence friction (<em>f </em>) would act in the opposite direction of the motion of the box. Tension (T) exist in the rope connecting the two boxes.

The free body diagram of box B is attached below showing all the forces acting on it.

harina [27]3 years ago
4 0
Ffriction B = frope > Ffriciton A
N = 1
F rope = 0.2
F Friction = 0.1
F worker = 0.3

F friciton A/ F friction B = 850/750

hope this helps
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3 years ago
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Answer:

λ = 5.65m

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δ= \sqrt{70^2+(33+\frac{20}{2})^2 }-\sqrt{70^2+(33-\frac{20}{2})^2 }

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δ= \sqrt{4900+(\frac{86}{2})^2 }-\sqrt{4900+(\frac{46}{2})^2 }

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δ= \frac{3*lamda}{2}

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