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frutty [35]
3 years ago
13

Explain how System 1 becomes equivalent to System 2.

Mathematics
1 answer:
LenKa [72]3 years ago
6 0

Answer:

In the procedure

Step-by-step explanation:

we have

<em>System 1</em>

Ax+By=C -----> equation A

Lx+My=N -----> equation B

<em>step 1</em>

Multiply equation B by -1 both sides

(-1)*(Lx+My=)N*(-1)

-Lx-My=-N ------> equation C

<em>step 2</em>

Adds equation A and equation C

Ax+By=C

-Lx-My=-N

----------------

Ax-Lx+By-My=C-N

(A-L)x+(B-M)y=C-N -----> equation D

step 3

An equivalent system (System 2) is formed with

Ax+By=C -----> equation A

(A-L)x+(B-M)y=C-N -----> equation D

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Solve for x and y<br>17) 2x - 3y = -1<br>y = x-1​
Cloud [144]

Answer:

x = 4 , y = 3

Step-by-step explanation:

Solve the following system:

{2 x - 3 y = -1 | (equation 1)

y = x - 1 | (equation 2)

Express the system in standard form:

{2 x - 3 y = -1 | (equation 1)

-x + y = -1 | (equation 2)

Add 1/2 × (equation 1) to equation 2:

{2 x - 3 y = -1 | (equation 1)

0 x - y/2 = (-3)/2 | (equation 2)

Multiply equation 2 by -2:

{2 x - 3 y = -1 | (equation 1)

0 x+y = 3 | (equation 2)

Add 3 × (equation 2) to equation 1:

{2 x+0 y = 8 | (equation 1)

0 x+y = 3 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 4 | (equation 1)

0 x+y = 3 | (equation 2)

Collect results:

Answer: {x = 4 , y = 3

4 0
4 years ago
A jar contains $36.25 in quarters and nickels. How many quarters and dimes are in the jar? Please explain how u got the answer,
kumpel [21]
So, look:

36*4 = 144

There are 145 quarters in all.

And in nickels, there are:

144 * 5 = 720 + 5 = 725
There are 725 nickels in all.

Dimes: 144 * 10 = 1440 + 10 = 1450  (or you could do 145 * 10 and still get 1450. Like I did in the nickels and everything. :) )

= 1450 dimes 

I hope this helps!

4 0
3 years ago
Match the polynomial expression on the left with the simplified version on the right.
Vitek1552 [10]

Given the following question:

First expression:

\begin{gathered} \frac{12x^3-14x^2+16x-8}{3x-2} \\ \text{ Factor the expression:} \\ 12x^3-14x^2+16x-8=2(6x^3-7x^2+8x-4) \\ \frac{2\left(6x^3-7x^2+8x-4\right)}{3x-2} \\ \text{ Factor:} \\ 2\left(6x^3-7x^2+8x-4\right)=(3x-2)(2x^2-x+2) \\ =(3x-2)(2x^2-x+2)=2\left(3x-2\right)\left(2x^2-x+2\right) \\ \frac{2\left(3x-2\right)\left(2x^2-x+2\right)}{3x-2} \\ \text{ Cancel the common factor:} \\ -(3x-2) \\ 4x^2-2x+4 \end{gathered}

Second expression:

3 0
1 year ago
A rational expression has been simplified below.
Margaret [11]
<span>The first thing to do here is simplify both sides. X=4/9 is simplified, but you can simplify the other side by canceling out the (x-2) in the numerator and denominator.

</span><span>The expression should be (x + 4)(x - 2)/9(x - 2)= (x + 4)/9. After simplification by (x - 2) , the remainder is (x + 4)/9. When x = -4, both sides equal to zero When x = 0 , both sides equal to 4/9
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
4 0
3 years ago
Read 2 more answers
What is the median of this data?
melisa1 [442]
The correct answer is 48
6 0
4 years ago
Read 2 more answers
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