Answer:
In the procedure
Step-by-step explanation:
we have
<em>System 1</em>
Ax+By=C -----> equation A
Lx+My=N -----> equation B
<em>step 1</em>
Multiply equation B by -1 both sides
(-1)*(Lx+My=)N*(-1)
-Lx-My=-N ------> equation C
<em>step 2</em>
Adds equation A and equation C
Ax+By=C
-Lx-My=-N
----------------
Ax-Lx+By-My=C-N
(A-L)x+(B-M)y=C-N -----> equation D
step 3
An equivalent system (System 2) is formed with
Ax+By=C -----> equation A
(A-L)x+(B-M)y=C-N -----> equation D