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larisa [96]
3 years ago
15

What is part of a line has one endpoint and continues in one direction?

Physics
1 answer:
noname [10]3 years ago
6 0

Answer:

A Ray I believe since it sounds like it.

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The mass of an atom is ________________________.
andreyandreev [35.5K]
I'd say d.) Concentrated in the nucleus.

This is because Nucleus consists of protons and neutrons; contributing to some mass, whereas Electron's mass is almost negligible ( 9.1 x 10^-31 kg) 

Hope this answers your question!
8 0
3 years ago
Melting ice caps can result in _____.
IceJOKER [234]

Melting of ice caps ... causing them to shrink in coverage .. can result in ...

-- wet ground

-- more farming opportunities, but less skiing

-- higher sea level

-- coastal flooding

-- extinction of plant and animal species

-- more icebergs floating around

-- lower average albedo, higher solar absorption, widespread warming

4 0
3 years ago
Read 2 more answers
A car makes a trip due north for three-fourths of the time and due south one-fourth of the time. The average northward velocity
jekas [21]

Answer:

v = 24.5 m

Explanation:

Average speed is defined as

       v = (x_{f} - x₀) / t

The distance is

        x = v t

In this case we can find the speed

       v = (v_nort ¾ t + v_sud ¼ t) / t

        v = 45 ¾ - 37 ¼

        v = 24.5 m

3 0
3 years ago
A 2550 pound roller coaster starts from rest and is launched such that it crests a 119 ft high hill with a speed of 57 mph. The
Feliz [49]

To solve this problem we will apply the concepts related to energy conservation. For this purpose we will have that all the changes occurred in the energy change will be equivalent to the change in the potential and kinematic energies of the body. At the same time we will consider that the change in the final energy of the system will be reflected in the work of the system, therefore,

\Delta E = KE+PE

E_i - Fd = \frac{1}{2}mv^2+Wh

Here,

F = Force

m = mass

v = Velocity

h = Height

d = Distance

W = mg \rightarrow \text{Weight/Force Weight}

E_i =\frac{1}{2}mv^2+Wh+Fd

E_i = \frac{1}{2} (\frac{W}{g})v^2 +Wh+fd

Replacing we have,

E_i = \frac{1}{2} (\frac{2550pounds}{32.2ft/s^2})(57mi/h(\frac{1.467ft/s}{1mi/h}))+(2550pounds)(119ft)+(100pounds)(583ft)

E_i =365061ft\cdot lb

Therefore the launch energy is 365061ft-lb

3 0
4 years ago
From Energy Graphs (LOLs) Again: Scenario 4 Hitting a Golf Ball
Vadim26 [7]
Just count the numbers
8 0
3 years ago
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