Answer:
I think
(d) All compounds contain the same elements in the same properties
Answer:
P2 = 19.2atm
Explanation:
Initial pressure (P1) = 16atm
Initial temperature (T1) = 340K
Final temperature (T2) = 408K
Final pressure (P2) = ?
This question involves the use of pressure law
Pressure law states that the pressure of a fixed mass of gas is directly proportional to it's temperature provided that volume is kept constant.
Mathematically,
P = kT, k = P / T
Therefore,
P1 / T1 = P2 / T2 = P3 / T3 = ......=Pn / Tn
P1 / T1 = P2 / T2
We need to solve for P2
P2 = (P1 × T2) / T1
Now we can plug in the values and solve for P2
P2 = (16 × 408) / 340
P2 = 6528 / 340
P2 = 19.2atm
The final pressure (P2) of the gas is 19.2atm
Moles ratio:
1 S<span> + 1 </span><span>O2</span><span> = 1 </span><span>SO<span>2
</span></span>
1 mole S -------------- 1 mole SO2
? moles S ------------ 0.567 moles SO2
0,567 x 1 / 1
= 0.567 moles of S
Answer:
1597,5 gm AlCl3 decomposed
Explanation:
2AlCl3 --> 2Al + 3Al2 If you produce 15 moles of Al, how many grams of AlCl3 decomposed?
FIRST, you need to write down the the correct reaction. Your equation makes no sense
here is the correct question
2AlCl3 --> 2Al + 3Cl2 If you produce 15 moles of Al, how many grams of AlCl3 decomposed?
for every mole of Al produced, we decomposed a mole of AlCl3
so we produced 15 moles of Al, so we decomposed 15 moles of AlCl3
15 moles are 15 X 106.5 = 1597,5 gm AlCl3 decomposed
