Answer is: the maximum concentration of Pb²⁺ is 6.8·10⁻³ M.
Chemical reaction 1: PbCl₂(s) → Pb²⁺(aq) + 2Cl⁻(aq).
Chemical reaction 2: NaCl(aq) → Na⁺(aq) + Cl⁻(aq).
Ksp(PbCl₂) = 1.7·10⁻⁵.
c(NaCl) = c(Cl⁻) = 0.0500 M.
Ksp(PbCl₂) = c(Pb²⁺) · c(Cl⁻)².
c(Pb²⁺) = Ksp(PbCl₂) ÷ c(Cl⁻)².
c(Pb²⁺) = 1.7·10⁻⁵ M³ ÷ (0.0500 M)².
c(Pb²⁺) = 0.000017 M³ ÷ 0.0025 M².
c(Pb²⁺) = 0.0068 M = 6.8·10⁻³ M.
Answer:
2. 14
Explanation:
To form Br₂ bond, a total of 14 electrons are needed.
Bromine is an element in the 7th group on the periodic table. It has 7 valence electrons.
- In forming the bromine gas, the two atoms of bromine shares 7 electrons each.
- These electrons are from their outermost shell.
- The outermost shell is the valence shell.
- So, two atoms donating 7 electrons gives 14 electrons.
Answer:
435.38 L
Explanation:
From the question given above, the following data were obtained:
Initial mole (n₁) = 3.25 mole
Initial volume (V₁) = 100 L
Final mole (n₂) = 14.15 mole
Final volume (V₂) =?
The final volume occupied by the gas can be obtained as follow:
V₁/n₁ = V₂/n₂
100 / 3.25 = V₂ / 14.15
Cross multiply
3.25 × V₂ = 100 × 14.15
3.25 × V₂ = 1415
Divide both side by 3.25
V₂ = 1415 / 3.25
V₂ = 435.38 L
Thus, the final volume of the gas is 435.38 L
The layer of Earth’s atmosphere that has the coldest temperature range is mesosphere